Box plots got me confused!! Help please due in 10 minutes!!

Mathematics

1 answer:

Pie3 years ago

6 0

First draw a line on the smallest number, and one on the largest. then calculate the midpoint (n+1)/2 the value, and draw that line in the middle. calculate upper quartile and lower quartile and draw lines on them. draw a line between the tops of the quartiles and one between the bottom, and from the middle of the lines to the minimum and maximum. sorry if not explained well

You might be interested in

For each rectangle below, write a linear equation that represents the area y of the rectangle. Solve this system of two linear e

Hatshy [7]

(5,24)

The two areas are the same.

To find the area, we multiply the side lengths. Y=area

Rectangle 1: side lengths 4 and (x+1)

y=4(x+1)= 4x+4

Rectangle 2: side lengths 3 and (2x-2)

y=3(2x-2)= 6x-6

Since the two areas are same, we can conclude that

4x+4=6x-6

Now, simplify.

-2x=-10, x=5

Since x is 5, we can plug it into the equations to find y.

Option 1 with rectangle 1: y=4(5)+4, y=24

Option 2 with rectangle 2: y=6(5)-5, y=24

I graphed the linear equation on desmos.

5 0

2 years ago

If possible help me in this. I need to find the two odd numbers...

Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer: x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\$