Question

Andrew can paint the neighbors house 6 times as fast as Bailey. the year Andrew and bailey worked together, it took them 5 days. how long would it take each to paint the house ?

Answer 1

Let Andrew be A and let Bailey be B
Andrew is 6 times as quick as Bailey
$1a = 6b$
When they worked together, it took them 5 days to paint the house.
$6b + 1b = 7b \\ 7b = 5days$
If Bailey worked alone, she would take a much longer time
$5 \times 7 = 35days$
Since Andrew is 6 times as quick as Bailey,
$\frac{(5 \times 7)}{6} = 5.8days$
Andrew would take about 5.8 days while Bailey would take 35 days.