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3 years ago

What is the answer to this question

Mathematics

1 answer:

Airida [17]3 years ago

8 0

the answer would be 67,127 because the number in the ones would be 7 and the tens number would be 2 since it wouldn't more than 1.

67,102

67,135

1-7

67,127

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Find the measure of angle b.

bija089 [108]

Answer:39

Step-by-step explanation:

90-51=39

4 0

3 years ago

For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger

11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = $p=\frac{1}{120}$ .

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

$P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...$

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}$

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166$

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410$

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803$

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419$

6 0

3 years ago

A contractor is building a pool labeled ABCD on the plans. If AC = 5y + 6 and BD = 8y-3, what value of y ensures the pool is a r

KIM [24]

The value of y that ensures the pool is a rectangle is 3. Option D

<h3>How to determine the value</h3>

The formula for perimeter of a rectangle is expressed as;

Perimeter = 2 ( length + width)

It is important to note that parallel sides of a rectangle are congruent, that is, they are equal.

Given the sides as;

AC = 5y + 6
BD = 8y-3

5y + 6 = 8y -3

collect like terms

5y - 8y = -3 - 6

-3y = -9

Make 'y' the subject

y = 3

Thus, the value of y that ensures the pool is a rectangle is 3. Option D

Learn more about rectangles here:

brainly.com/question/25292087

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3 0

1 year ago

What is the volume of the right rectangle prism?

tatiyna

Length times width times height

6*9*2
104

6 0

3 years ago

Based on the family the graph below belongs to, which equation could represent the graph?

FrozenT [24]

Considering the asymptotes of the function, the equation that represents the graph is:

$y = \frac{1}{x + 2} + 3$

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

This function, from the graph, has a vertical asymptote at x = -2, hence the denominator is given by: $y = \frac{1}{x + 2} + 3$

x + 2, as x + 2 = 0 -> x = -2.

The horizontal asymptote is of y = 3, hence:

$\lim_{x \rightarrow \infty} f(x) = 3$

Which means that the function is described by the following rule:

$y = \frac{1}{x + 2} + 3$

More can be learned about asymptotes at brainly.com/question/16948935

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7 0

1 year ago