T=0 is also a solution. Other than 0 here is a solution.
Its 5x30=y or =30=y so thats it
Answer:
f + g)(x) = f (x) + g(x)
= [3x + 2] + [4 – 5x]
= 3x + 2 + 4 – 5x
= 3x – 5x + 2 + 4
= –2x + 6
(f – g)(x) = f (x) – g(x)
= [3x + 2] – [4 – 5x]
= 3x + 2 – 4 + 5x
= 3x + 5x + 2 – 4
= 8x – 2
(f × g)(x) = [f (x)][g(x)]
= (3x + 2)(4 – 5x)
= 12x + 8 – 15x2 – 10x
= –15x2 + 2x + 8
\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(
g
f
)(x)=
g(x)
f(x)
= \small{\dfrac{3x+2}{4-5x}}=
4−5x
3x+2
My answer is the neat listing of each of my results, clearly labelled as to which is which.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}
Answer: D: x = (-9, 0) U (0, 4) U (4, 8)
<u>Step-by-step explanation:</u>
Line 1: y = -2 where -9 < x < 0
Line 2: y = 2)x + 1 where 0 < x < 4
Line 3: y = -(1/2)x + 6 where 4 < x < 8
Domain represents the x-values. Since all of them are open dots, the intervals are strictly less than (<).
-9 < x < 0 and 0 < x < 4 and 4 < x < 8 is the union of these intervals
-9 < x < 0 U 0 < x < 4 U 4 < x < 8
Interval Notation: D: x = (-9, 0) U (0, 4) U (4, 8)