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Karo-lina-s [1.5K]
3 years ago
15

$5.42 in change. How much did each bag of chips cost?

Mathematics
2 answers:
taurus [48]3 years ago
4 0

Answer: 2.71

Step-by-step explanation: I just got done taking a test about this

Gnoma [55]3 years ago
3 0

Answer:

$2.71

Step-by-step explanation:

Hey!

I multiplied $2.71 by 2 and that gave me $5.42

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a cubic box has a side length of 2 feet. How many of these boxes could fit inside a larger cubic box whose base has a perimeter
kap26 [50]
So if a cubic box has a side length of 2 ft in order to find the volume we need to cube it or multiply the length times 3 times. so it would be 2x2x2=8. that is the volume of the fiest cube. in order to find the volume of the larger cube first you need to know the length of one of the sides. the base has 4 sides to it that are all equal so you divide 24 by 4 and get 6. then to find the volume you multiply 6 three times since it is also a cubic cube so it would be 6x6x6=216. now you know the volume of each cube so you divide 216 by 8 to find how many times the volume of the small cube would go into the volume of the larger cube and get 27 times.
6 0
3 years ago
To qualify for the championship a runner must complete the race in less than 55 minutes ....... Use "t" to represent the time in
Svet_ta [14]

The inequality is t < 55

<em><u>Solution</u></em><em><u>:</u></em>

Given that, To qualify for the championship a runner must complete the race in less than 55 minutes

Let "t" represent the time in minutes of a runner who qualifies for the championship

Here it is given that the value of t is less than 55 minutes

Therefore, "t" must be less than 55, so that the runner qualifies the championship

<em><u>This is represented by inequality:</u></em>

t

The above inequality means, that time taken to complete the race must be less than 55 for a runner to qualify

Hence the required inequality is t < 55

3 0
3 years ago
Solve.<br>22 + 6-1<br>Your answer​
Nimfa-mama [501]

Answer:

27

Step-by-step explanation:

22 + 6 = 28 - 1 = 27

6 0
3 years ago
Read 2 more answers
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

4 0
3 years ago
Write down the first five terms of the AP with first term 5 and common difference 7 ​
Zigmanuir [339]

Answer:

Hvrbfbkkeuhevejhesseefj

5 0
3 years ago
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