1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddika [18.5K]
3 years ago
9

The temperature outside was 60 degrees when Sarah woke up. By noon, it had increased to 75 degrees.

Mathematics
1 answer:
Tom [10]3 years ago
4 0
It is a 0.25 increase. Plz plz plz give me brainiest answer I only need 4 more to rank up. If u do I will show my work.
You might be interested in
In yoshi's garden, 3/4 of the flowers are tulips. Of the tulips, 2/3 are yellow. What fraction of the flowers in Yoshi's garden
sergiy2304 [10]
The answer is 1/2. I hope i helped
3 0
3 years ago
A carpenter needs to cut two pieces of trim around a window at 34 3/8 inches each. If the saw blade will remove 1/8 of an inch o
Yuki888 [10]

Answer:

It is so ez, it is of course 2

Step-by-step explanation:

3 0
3 years ago
Help me with math work please
shutvik [7]

2. b=-15   4. b=9   5. m=6 b=1   6. m=-4 b=140

6 0
3 years ago
Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of
Misha Larkins [42]

This question is incomplete, the complete question is;

Assume that body masses of Goldfinch birds follow a normal distribution, with a standard deviation equal to 0.04 oz. An ornithologist who would like to make some inference about the average body mass of the Goldfinch birds. In particular, at a significance level of 0.01, she would like to test the null hypothesis H₀: Average body mass of the Goldfinch birds is 0.5 oz, against the alternative claim that average body size is less than 0.5 oz.

      Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of the sample mean, that will allow the experimenter reject the null and prove the alternative at significance level 0.01. For this problem, make sure that your solution includes all steps of your computation. You will not earn points if you just use a formula

Answer: the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

Step-by-step explanation:

Let us consider testing a hypothesis about a population mean with population standard deviation that is known,

Let the average body mass of the Goldfinch bird be μ^μ

Now our hypotheses are will be;

H₀ : μ = 0.5    and

H₁ : μ < 0.5

For the test, we shall use the z statistic which will be

z = (x"-μ)/(σ/√n)

Now given that;

σ = 0.04 and n = 4  

sample mean x" = ?

Now in order to be able to reject the null hypothesis, the p-value should be ≤ α = 0.01.

so to find the largest value of sample mean, we will use the maximum of p-value that is 0.01.

For a p-value = 0.01 at the lower tail (which is the percentile for z),

the corresponding z will be -2.33

so we substitute our values into our formula

z = (x"-μ)/(σ/√n)

z(σ/√n) = (x"-μ)

-2.33(0.04/√n) = (x"-0.5)

-0.0466 = x" - 0.5

x" = 0.5 - 0.0466

x"= 0.4534

therefore the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

4 0
3 years ago
A sociologist develops a test to measure attitudes towards public transportation, and 27 randomly selected subjects are given th
taurus [48]

Answer:

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0518

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample.

In this question:

n = 27, s = 21.4. So

M = 2.0518\frac{21.4}{\sqrt{27}}

M = 8.45

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

5 0
3 years ago
Other questions:
  • I know it’s kinda blurry but if you can see it plz help me
    13·1 answer
  • Question 3
    5·1 answer
  • A 15 foot ladder is leaning against a wall. if the foot of the ladder is sliding away from the wall at a rate of 10 ft/sec, at w
    13·1 answer
  • Between 1995 and 2000, the average price of a house in Middlebury went up from $100,000 to $120,000. What was the percentage inc
    9·1 answer
  • If you reverse the digits of a two-digit positive integer and subtract the resulting integer from the original integer , the dif
    11·1 answer
  • 13. Consider the following sequence, f(n) = 7, 28, 112, 448, ..., where f(n) represents then
    14·1 answer
  • How many meters are in a hectometer
    9·2 answers
  • Subtract and write in standard form<br>(8x – 6x3 + 5x2) - (2x2 + 2x - 7x3)​
    12·1 answer
  • -Which equation is shown by the information in the table?
    9·1 answer
  • How long is the arc intersected by a central angle of startfraction pi over 3 endfraction radians in a circle with a radius of 6
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!