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3 years ago

TAKING A TEST COULD REALLY USE THE HELP URGENTLY

Mathematics

2 answers:

motikmotik3 years ago

8 0

Answer:

I think its the third one but im not entirely sure

Step-by-step explanation:

Alex777 [14]3 years ago

3 0

The answer is C.

The circle is empty, so we know it's either greater than or less than.

It's pointing right, so we know it has to be greater than or including all values bigger than.

Taking all that into account, the only answer that is appropriate is C or x > 5.

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-10b + 5 = 7b + 5 .<br> ANSWER ASAP<br> Show step by step on paper please.

Lynna [10]

Answer:

your answer should be b= 17

3 0

3 years ago

a paper company needs to ship paper to a large printing business the paper will be shipped in small boxes in large boxes the vol

stepan [7]

Answer:

the answer is 10 :)

Step-by-step explanation:

5 0

2 years ago

Pls can someone help me‼️‼️‼️‼️<br> and I don’t want files.

ANEK [815]

Answer:

135

Step-by-step explanation:

a line always has a degree of 180 so u just subtract 45 from 180 and get 135

5 0

3 years ago

For all values of x f(x)

Firlakuza [10]

Answer:

f(g(5)) = 64

g(f(5)) = 28

Step-by-step explanation:

Given that f(x) = x^2 and g(x) = x+3

f(g(x) = f(x+3)

f(x+3) = (x+3)^2

f(g(x)) = (x+3)^2

f(g(5)) = (5+3)^2

f(g(5)) = 8^2

f(g(5)) = 64

b) g(f(x)) = g(x^2)

g(f(x)) = x^2 + 3

g(f(5)) = 5^2 +3

g(f(5)) = 25 + 3

g(f(5)) = 28

Hence the value of g(f(5)) is 28

5 0

3 years ago

A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop

attashe74 [19]

Answer:

$0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286$

$0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562$

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

$X= 36$ represent the families owned at least one DVD player

$n= 85$ represent the total number of families

$\hat p=\frac{36}{85}= 0.424$ represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286$

$0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562$

The 99% confidence interval would be given by (0.286;0.562)

8 0

3 years ago