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amid [387]
3 years ago
8

A If a ¥ b = b find 10 ¥ 2 3

Mathematics
1 answer:
solong [7]3 years ago
3 0

Answer:

what is meaning of ¥?...................

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an experiment consists of flipping a fair coin 4 times. What is the probability of obtaining at least one head?
Dvinal [7]
\mathbb P(X\ge1)=1-\mathbb P(X=0)

The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is \dfrac1{2^4}=\dfrac1{16}.

So the desired probability is

1-\dfrac1{16}=\dfrac{15}{16}
7 0
3 years ago
Please help me The difference of two numbers is 9. If the larger number is one more than twice the smaller number, find the lage
Helen [10]

Answer:

17

Step-by-step explanation:

Let the larger number be represented by x

Let the smaller number be represented by y

from the question, the next equations can be gotten :

x - y = 9  equation 1

x = 1 + 2y equation 2

Substitute for x in equation 1

1 + 2y - y = 9

1 + y = 9

Collect like terms

y = 9 - 1

y = 8

Substitute for y in equation 1 and solve for x (the larger number)

x - 8 = 9

x = 9 + 8

x = 17

6 0
3 years ago
More than half of the students were excited about the project. In fact, were excited. If 10 students were not
alina1380 [7]

Answer:1/2 divided by 10

Step-by-step explanation:

8 0
2 years ago
. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
3 years ago
The circus travels 15 miles in 45 minutes what is her MPH
ch4aika [34]

Answer: HER MPH is 20

8 0
3 years ago
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