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3 years ago

9

Complete the square.

" alt="t^{2} -24t+ ?" align="absmiddle" class="latex-formula">

1 answer:

irina [24]3 years ago

8 0

Answer: (x-12)^2-144

Step-by-step explanation:

use the formula (b/2)^2 in order to create a new term to complete the square.

LET ME KNOW IF ITS RIGHT

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Heplllllll on 2 3 4 5

sveticcg [70]

Change them into improper fractions
and then find a common denominator, then minus, add, whatever for each one

7 0

3 years ago

Find the point of Intersection of two lines<br> Y= 4x + 1 and Y 2x + 7

satela [25.4K]

Answer:

(3, 13)

Step-by-step explanation:

i plugged the two lines into desmos :)

5 0

2 years ago

Read 2 more answers

Find the value of n in this equation.

lisabon 2012 [21]

Answer:

D. 9

=========================

<h2>Given </h2>

Triangle with:

Base of n² -3,
Midsegment of 39.

<h2>To find</h2>

The value of n.

<h2>Solution</h2>

As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.

So we have:

(n² - 3)/2 = 39

Solve it for n:

n² - 3 = 78
n² = 81
n = √81
n = 9

Correct choice is D.

3 0

1 year ago

Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of

Luda [366]

Answer:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

$|C| = \sqrt{a^2+b^2}$

Then, the work consists in finding pairs (a,b) for which:

$\sqrt{a^2+b^2}=3$

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

$\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}$

I will use b =0.5, b = 1, b = 1.5, b = 2

$b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236$

Then, four distinct complex numbers that have an absolute value of 3 are:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

4 0

3 years ago

Which is the graph of the function f(x) = x^3 + 6x^2 + 11x + 6?

Ganezh [65]

Here you go.. hope this helps

4 0

3 years ago