The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
The correct answer is: AB = 3.11
Explanation:
Since
--- (1)
= 50°
base = 2
And hypotenuse = AB
Plug in the values in (1):
(1) => cos(50°) = 2/AB
=> AB = 2/0.643
=> AB = 3.11
Answer:
Step-by-step explanation:
= 
or 81.
Answer:
14.44 (Letter D)
Step-by-step explanation:
The answer is 14.44
Hopefully its correct!!!
