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3 years ago

Round 202.366 to the nearest hundredth

1 answer:

3 0

Hello there,

202.366 to the nearest hundredth would be 202.37.

So what I did was I look at the 366 in the problem.

We want to round the to the nearest hundredth.

So what we would do it notice how the 66 in over 50.

The rule is if it's over 50, we round it to the nearest.

So your answer would be 202.37.

Hope this helps.

~Jurgen

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What is the midpoint of (-23,-14) and (-18,2)

zloy xaker [14]

Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).

To find the midpoint we would use the formula below;

$\text{midpoint(x,y)}=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Where x1=-23, x2=-18, y1=-14, y2=2

We would substitute the values into the midpoint formula.

$\begin{gathered} \text{midpoint =(}\frac{-23-18}{2},\frac{-14+2}{2}) \\ =(-\frac{41}{2},-6) \end{gathered}$

Therefore, the answer is

$\text{midpoint}=(-\frac{41}{2},-6)$

7 0

1 year ago

The table shows a student's proof of the quotient rule for logarithms.

nikklg [1K]

Answer:

The error is at step (3) .

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

Step-by-step explanation:

The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

5 0

3 years ago

For what values of x does the binomial 2x−1 take on a positive value?

Mashutka [201]

1). 2x-1>0
2x>1
x>½

2) 21-3y<0
-3y<-21
y>7

3) 5-3c>80
-3c>75
c<-25

3 0

3 years ago

Sam can prepare 20 wall paintings in 4 weeks. How much time will he need to

Nadusha1986 [10]

Answer:
20=4 weeks
40=8 weeks
60=12 weeks
80=16 weeks
Hope I helped :)

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3 years ago

Your parents car initially costs $18,000 and it depreciates at a rate of 12% a year. How much will the car be worth after 5 year

coldgirl [10]

Answer:

Step-by-step explanation:

value after five years = $18,000×(1-0.12)⁵ = 18,000×0.88⁵ = $9,499.17

:::::

The value drops below $2,000 in the 17th year.

7 0

2 years ago