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MArishka [77]
2 years ago
13

Why do you have a premium? That's :(

Mathematics
2 answers:
tekilochka [14]2 years ago
5 0

Answer:

i dont have a premium

Step-by-step explanation:

GaryK [48]2 years ago
4 0

Answer:

Step-by-step explanation:

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What is the distributive property of 2 times 8
malfutka [58]
2*8 using <span>distributive property
= 2(3+5)
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= 16</span>
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3 years ago
In how many ways can you park 4 different cars at a car park with 5 different parking spaces?
meriva
1. If you have 1 first then... 1,2,3,4 - 1,3,2,4 - 1,2,4,3 - 1,3,4,2 - 1,4,3,2 - 1,4,2,3
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5 0
2 years ago
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
20 POINTS PLZ HELP!!!!!!!!!!!!!!!!!!!!
mars1129 [50]

Answer:

a = 15

Step-by-step explanation:

First, you have to combine like terms: 5a and 3a, -5, -15, 6, and 4.

You can do it in any order and you will always get a = 15 for your answer.

Hope this helps!!!

3 0
3 years ago
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Sonbull [250]

Answer:

y=-2/3x-3 is the equation in slope intercept form

Step-by-step explanation:

Hope this helps (:

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2 years ago
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