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3 years ago

Jay made 8 of 10 free throws.Kim made 25 of 45.Who made free throws at a better rate?How do you know?

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

Jays rate=80% kims rate=55.6% jay has a better rate take the number made and divide it by the number thrown.

murzikaleks [220]3 years ago

5 0

Kim’s rate jay made 4/5 kim 2.5/5

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a random sample of 510 high school students has a normal distribution. The sample mean average ACT exam score was 21 with a 3.2

34kurt

Answer:

CI = 21 ± 0.365

Step-by-step explanation:

The confidence interval is:

CI = x ± SE * CV

where x is the sample mean, SE is the standard error, and CV is the critical value (either t score or z score).

Here, x = 21.

The standard error for a sample mean is:

SE = σ / √n

SE = 3.2 / √510

SE = 0.142

The critical value is looked up in a table or found with a calculator. But first, we must find the alpha level and the critical probability.

α = 1 - 0.99 = 0.01

p* = 1 - (α/2) = 1 - (0.01/2) = 0.995

Using a calculator or a z-score table:

P(x<z) = 0.995

z = 2.576

Therefore:

CI = 21 ± 0.142 × 2.576

CI = 21 ± 0.365

Round as needed.

8 0

3 years ago

How can the logarithmic expression be rewritten? Select True or False for each statement.

topjm [15]

Answer:

True, True, False

Step-by-step explanation:

5 0

2 years ago

Factor 12q^2+34q-28. Include list of factors.

Misha Larkins [42]

Answer:

2(2q+7)(3q-2)=0

Step-by-step explanation:

lets set up the equation equal to 0:

12q^2+34q-28=0

now, lets factor:

2(6q^2+17q-14)=0

2(2q+7)(3q-2)=0

now, lets find the solutions:

2q+7=0

2q=-7

q=-3.5

3q-2=0

3q=2

q=2/3

5 0

3 years ago

The center is a typical value. It is the _______________ value of a dot plot.

larisa [96]

When referring to a dot plot, scatter graph, or scatter plot such as this one, the line that represents the averages of all Y values is known as a line of best fit.

Hope this helps,

Jeron

6 0

2 years ago

Read 2 more answers

The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05

Tresset [83]

Answer:

(a) Probability that there are no surface flaws in an auto's interior is 0.6065 .

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws is 0.00673 .

Step-by-step explanation:

We are given that the number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.05 flaws per square foot of plastic panel.

Let X = Distribution of number of surface flaws in plastic panels

So, X ~ Poisson( $\lambda$ )

The mean of Poisson distribution is given by, E(X) = $\lambda$ = 0.05

which means, X ~ Poisson(0.05)

The probability distribution function of a Poisson random variable is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!}; for x=0,1,2,3...$

Now, we know that $\lambda$ for per square foot of plastic panel is 0.05 and we are given that an automobile interior contains 10 square feet of plastic panel.

Therefore, for 10 square foot of plastic panel is = 10 * 0.05 = 0.5

(a) Probability that there are no surface flaws in an auto's interior =P(X=0)

P(X = 0) = $\frac{e^{-0.5}*0.5^{0}}{0!}$ = $e^{-0.5}$ = 0.6065

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws = $P(X = 0)^{10}$

So, $P(X = 0)^{10}$ = $0.6065^{10}$ = 0.00673

8 0

3 years ago