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levacccp [35]
3 years ago
7

Identify a possible measure of the reference angle sketched in standard position

Mathematics
1 answer:
iragen [17]3 years ago
6 0
The first answer is correct
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Y=4x+3 table of ordered pairs
lara31 [8.8K]

Answer:

X:1 2 3 4 5 Y:7 11 15 19 23.

Step-by-step explanation:

We just need to put in the values of x into the equation: y = 4x + 3.

<u>x = 1: </u>

y = 4(1) + 3

  = 4 + 3

y = 7

<u>x = 2: </u>

y = 4(2) + 3

  = 8 + 3

y = 11

<u>x = 3:</u>

y = 4(3) + 3

  = 12 + 3

y = 15

<u>x = 4:</u>

y = 4(4) + 3

  = 16 + 3

y = 19

<u>x = 5:</u>

y = 4(5) + 3

  = 20 + 3

y = 23

6 0
3 years ago
Consider the two functions given below.
mestny [16]
This means which transformation makes the same answer at x = 0

f(x) = 3x + 4
g(x) = {2}^{x}  - 1

f(0) = 4
g(0) = 1 - 1 = 0

Which transformation makes 4 = 0?

4 + x = 0 + y

4 - 3 =0 + 1

1 = 1

Option 1 is your answer
3 0
3 years ago
Read 2 more answers
Megan said the opposite of the sum of -12 and 4 is 8.
jasenka [17]

Megan is correct. -12 + 4 is -8 and the opposite of that is 8

8 0
3 years ago
Read 2 more answers
Kyla made 15 cups of pudding for a class. If there are 20 students in the class, how much with each student get? Write your answ
harina [27]
3/4 a cup
I believe this is the answer
7 0
3 years ago
Read 2 more answers
Find the P-value for a test of the claim that more than 60% of the people following a particular diet will experience increased
lina2011 [118]

Answer:

The p-value of the test is 0.0207.

Step-by-step explanation:

Test of the claim that more than 60% of the people following a particular diet will experience increased energy (H1: p > 0.6).

The null hypothesis is:

H_0: p = 0.6

The alternate hypothesis is:

H_1: p > 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that \mu = 0.6, \sigma = \sqrt{0.6*0.4}

Of 100 randomly selected subjects who followed the diet, 70 noticed an increase in their energy level.

This means that n = 100, X = \frac{70}{100} = 0.7

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.7 - 0.6}{\frac{\\sqrt{0.6*0.4}}{\sqrt{100}}}

z = 2.04

P-value of the test:

The p-value of the test is the probability of finding a sample proportion of at least 0.7, which is 1 subtracted by the p-value of z = 2.04.

Looking at the z-table, z = 2.04 has a p-value of 0.9793

1 - 0.9793 = 0.0207

The p-value of the test is 0.0207.

4 0
3 years ago
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