Added all that up and you get 680$
hope this helps
The differnce quotient is basically taking the derivitive (result will be f'(x)=5, but anyway)
here is the disffernce quotient
![lim_{h\rightarrow0}\frac{f(x+h)-f(x)}{h}](https://tex.z-dn.net/?f=lim_%7Bh%5Crightarrow0%7D%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D)
so
for your equation
![lim_{h\rightarrow0}\frac{(5(x+h)+4)-(5x+4)}{h}](https://tex.z-dn.net/?f=lim_%7Bh%5Crightarrow0%7D%5Cfrac%7B%285%28x%2Bh%29%2B4%29-%285x%2B4%29%7D%7Bh%7D)
![lim_{h\rightarrow0}\frac{5x+5h+4-5x-4}{h}](https://tex.z-dn.net/?f=lim_%7Bh%5Crightarrow0%7D%5Cfrac%7B5x%2B5h%2B4-5x-4%7D%7Bh%7D)
![lim_{h\rightarrow0}\frac{5h}{h}](https://tex.z-dn.net/?f=lim_%7Bh%5Crightarrow0%7D%5Cfrac%7B5h%7D%7Bh%7D)
h's cancel and you are left with 5
the differnce quotient is 5
In this case, the vector is passing through a right angle as shown with the little square on the left side. (all right angles equal 90 degrees) so you would simply subtract 64 from 90. (90 - 64 = 26) so x equals 26 degrees.
Potential Energy of an object of 5kg which is 6 meters in height is 294 Joules.
Step-by-step explanation:
We are given:
Mass = m = 5 kg
Height = h= 6 meters
Potential Energy = ?
The formula used to find Potential Energy is:
![Potential\,\,Energy =mgh](https://tex.z-dn.net/?f=Potential%5C%2C%5C%2CEnergy%20%3Dmgh)
where m is mass, g is gravitational field and h is height
Putting the given values of mass and height, and g=9.8 m/s^2
![Potential Energy = 5*9.8*6\\Potential Energy = 294 Joules](https://tex.z-dn.net/?f=Potential%20Energy%20%3D%205%2A9.8%2A6%5C%5CPotential%20Energy%20%3D%20294%20Joules)
So, Potential Energy of an object of 5kg which is 6 meters in height is 294 Joules.
Keywords: Potential Energy
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