Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
Let x = The age of Michael
Let 2x-3 = The age of Michaels cousin
X+2x-3=46
x=16+1/3
X = 49 years
I think that’s the answer I’m not 100% sure though
Add the length width and height all together
Answer:
Angle A is 29 degress Angle B is 61 Angle C is 90
Side AB is 5.8 Side BC is 2.8 and Side AC is 5.1
Step-by-step explanation:
Angle A is found using triangle interior theorem.
I found side AC by using law of sines
b/sin b= c/sin c
x/sin 61= 5.8/sin 90( which equal 1)
x=5.1
I found side BC by using pythagoren theorem.
a^2 + b^2=c^2
5.1^2+ b^2=5.8^2
26.01+b^2=36.64
b^2=7.63
b=approx 2.8.
