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lbvjy [14]
3 years ago
5

Which units can be used to measure length or distance? Check all that apply.

Physics
2 answers:
MakcuM [25]3 years ago
6 0

Answer:

meter

kilometer

inch

Explanation:

shtirl [24]3 years ago
4 0
Gram meter inches and kilometer
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A parallel-plate vacuum capacitor has 8.38 j of energy stored in it. the separation between the plates is 2.30 mm. if the separa
avanturin [10]
<h3><u>Answer;</u></h3>

= 4.19 Joules

<h3><u>Solution;</u></h3>

Energy stored in capacitor = U = 8.38  J

U =(1/2)CV^2

C =(eo)A/d

C*d=(eo)A=constant

C2d2=C1d1

C2=C1d1/d2

Initial separation between the plates =d1= 2.30mm .  

Final separation = d2 = 1.15 mm

But; Energy=U =(1/2)q^2/C  

U2C2 = U1C1

U2 =U1C1 /C2

U2 =U1d2/d1

Final energy = Uf = initial energy × d2/d1

                                = 8.38 ×1.15/2.30

                                = 4.19 Joules

Thus; The final energy = 4.19 Joules

6 0
4 years ago
Read 2 more answers
A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.
Nataliya [291]

To solve the exercise it is necessary to take into account the definition of speed as a function of distance and time, and the speed of air in the sound, as well

v=\frac{d}{t}

Where,

V= Velocity

d= distance

t = time

Re-arrange the equation to find the distance we have,

d=vt

Replacing with our values

d= (343)(3.7)

d= 1269.1m

It is understood that the sound comes and goes across the entire lake therefore, the length of the lake is half the distance found, that is

L_{lake} = \frac{d}{2}

L_{lake} = \frac{1269.1}{2}

L_{lake} = 634.55m

Therefore the length of the lake is 634,55m

8 0
4 years ago
What is the length of the x-component of the vector shown below?
kondaur [170]

If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is

x-component = 88 · cosine(13°)

x-component = 88 · (0.9744)

<em>x-component = 85.74</em>

5 0
3 years ago
Read 2 more answers
What is the wavelength for this wave?
Alexus [3.1K]

Answer:

160

Explanation:

6 0
3 years ago
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Newton measured the centripetal acceleration of the moon in its orbit around Earth by comparing the force Earth exerts on the mo
telo118 [61]

Answer:

G = 6.64*10^{-11} Nm^2/kg^2

Explanation:

According to Newton 2nd law of motion: F = ma where m is the mass of the moon and a is the centripetal acceleration of the gravitational force.

Also Gravitational force formula

F_g = G\frac{m*ME}{S^2} where G is the gravitational force, ME is the mass of Earth and S is the mean distance between Earth and Moon.

As the moon is at constant circular motion around Earth, there forces balance out:

F = F_g

ma = G\frac{m*ME}{S^2}

G = \frac{S^2*a}{ME}

We can now substitute S = RME = 3.86*10^8 m and a = ac = 2.66*10^{-3} m/s^2 and ME = 5.97 * 10^{24} kg

G = \frac{(3.86*10^8)^2*2.66*10^{-3}}{5.97 * 10^{24}}

G = 6.64*10^{-11} Nm^2/kg^2

3 0
3 years ago
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