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kow [346]
3 years ago
11

A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.

She hears the echo 3.7s\; s after shouting. The speed of sound in air is 343 m/s\rm m/s. Determine the length of the lake. Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
Nataliya [291]3 years ago
8 0

To solve the exercise it is necessary to take into account the definition of speed as a function of distance and time, and the speed of air in the sound, as well

v=\frac{d}{t}

Where,

V= Velocity

d= distance

t = time

Re-arrange the equation to find the distance we have,

d=vt

Replacing with our values

d= (343)(3.7)

d= 1269.1m

It is understood that the sound comes and goes across the entire lake therefore, the length of the lake is half the distance found, that is

L_{lake} = \frac{d}{2}

L_{lake} = \frac{1269.1}{2}

L_{lake} = 634.55m

Therefore the length of the lake is 634,55m

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mafiozo [28]

Answer:

The second wavelength is 482 nm.

Explanation:

Given that,

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Distance from central maxim of another wavelength = 0.39 m

We need to calculate the second wavelength

Using formula of width of fringe

\beta=\dfrac{\lambda d}{D}

Here, d and D will be same for both wavelengths

\lambda = wavelength

\beta = width of fringe

The width of fringe for first wavelength

\beta_{1}=\dfrac{\lambda_{1} d}{D}....(I)

The width of fringe for second wavelength

\beta_{2}=\dfrac{\lambda_{2} d}{D}....(II)

Divided equation (I) by equation (II)

\dfrac{\beta_{1}}{\beta_{2}}=\dfrac{\lambda_{1}}{\lambda_{2}}

\lambda_{2}=\dfrac{630\times10^{-9}\times0.39}{0.51}

\lambda_{2}=4.82\times10^{-7}

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Hence, The second wavelength is 482 nm.

4 0
3 years ago
A brick 25cm long ,9cm wide 5cm thick has a mass of 1000g determine the greatest pressure that can be exerted by the brick on a
lana66690 [7]

Answer:

<em>The greatest pressure is 2178 Pa</em>

Explanation:

<u>Pressure</u>

It's the force applied perpendicular to the surface of an object per unit area over which the force is distributed.

If F is the force applied and A is the surface area, the pressure is calculated as:

\displaystyle P=\frac{F}{A}

The brick has dimensions of 25 cm by 9 cm by 5 cm. There are three possible areas of contact:

A_1=25*9 = 225 cm^2=0.0225\ m^2

A_2=25*5= 125 cm^2=0.0125\ m^2

A_3=9*5= 45 cm^2=0.0045\ m^2

The  brick has a mass of m=1000 g = 1 Kg and exerts a force equal to its weight when placed on a flat surface, thus:

F = m.g = 1 * 9.8 = 9.8 N

The greatest possible pressure will occur when the area is the least possible (0.0045\ m^2), since the pressure and the area are inversely proportional, thus:

\displaystyle P_{max}=\frac{9.8}{0.0045}

\displaystyle P_{max}=2178 \ Pa

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ANSWER THIS FOR BRAINY CROWN B) ITS SO EASY!
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Answer:

300

Explanation:

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as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies. true or false?
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Answer:

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Therefore , as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies is a false statement.

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