Question

Please help with this algebra question

Answer 1

Perimeter: P=24 ftLenght: LWidth: W
The length is 2 ft longer than the width:(1) L= W+2 ft
Perimeter: P=2(W+L)P=24 ft2(W+L)=24 ftDividing both sides of the equation by 2:2(W+L)/2 =(24 ft)/2(2) W+L=12 ft
We have a system of 2 equations and 2 unkowns:(1) L=W+2(2) W+L=12
Using the method of substitution: Replacing L by W+2 in the second equation:(2) W+L=12W+(W+2)=12W+W+2=122W+2=12
Solving foe W2W+2-2=12-22W=10Dividing both sides of the equation by 2:2W/2=10/2W=5
Replacing W by 5 in the first equation:(1) L=W+2L=5+2L=7
Answers:What is the width?  5 ftWhat is the length? 7 ft