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weeeeeb [17]
3 years ago
13

F(x) = 49 − x2 from x = 1 to x = 7; 4 subintervals

Mathematics
1 answer:
Setler [38]3 years ago
3 0

Answe

Given,

f(x) = 49 − x² from x = 1 to x = 7

n = 4

\Delta x = \dfrac{7-1}{4}= 1.5

For x= 1

f(x₀) = 49 - 1^2 = 48

x = 2.5

f(x₁) = 42.75

x = 4

f(x₂) = 49 - 4^2 = 33

x = 5.5

f(x₃) = 49 - 5.5^2 = 18.75

x = 7

f(x₄) = 49 - 7^2 = 0

We have to evaluate the function on therigh hand point

A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]

A = 1.5 [42.75+33+18.75+0]

A = 141.75

For Area for left hand sum

A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]

A = 1.5 [48+42.75+33+18.75]

A =213.75

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Answer:

11.5

Step-by-step explanation:

We solve using :

Pythagoras Theorem

LM² = MN² + NL²

NL² = LM² - MN²

NL = √LM² - MN²

NL = √14² - 8²

NL =  √(132)

NL = 11.489125293

NL = 11.5

Therefore, the length of NL = 11.5

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3 years ago
Section J in an arena has 20 rows each row has 15 seats all tickets cost $18 each if all the seats are sold, how much money will
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3 years ago
will the contents of a cylindrical can of soup with a 1.5-inch radius and a 5-inch height fit into a pan with a 4-inch radius an
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Answer:

Answer: The volume of the soup can is less that that of the pan, so the soup will fit in the pan.

Step-by-step explanation:

a. V = s3

V = (7 km)3

V = 7 km × 7 km × 7 km

V = 343 km3

b. V = s3

V = (11 yd.)3

V = 11 yd. × 11 yd. × 11 yd.

V = 1,331 km cu. yd.

a. V = l × w × h

V = 6 m × 2 m × 3 m

V = 36 m3

b. V = l × w × h

V = 5 ft. × 10 ft. × 8 ft.

V = 400 cu. ft.

a. V = πr2h

V = 3.14 × (3 in.)2 × 3 in.

V = 3.14 × 9 sq. in. × 3 in.

V = 84.78 cu. in.

b. V = πr2h

V = 3.14 × (1 m)2 × 4 m

V = 3.14 × 1 m2 × 4 m

V = 12.56 m3

V = s3

V = (2 ft.)3

V = 2 ft. × 2 ft. × 2 ft.

V = 8 cu. ft.

Answer: The capacity of the ice chest is 8 cubic feet.

V = πr2h

V = 3.14 × (1 ft.)2 × 3 ft.

V = 3.14 × 1 sq. ft. × 3 ft.

V = 9.42 cu. ft.

Answer: The volume of the trash can is 9.42 cubic feet.

Closet #1

V = l × w × h

V = 4 ft. × 5 ft. × 8 ft.

V = 160 cu. ft.

Closet #2

V = l × w × h

V = 6 ft. × 3 ft. × 8 ft.

V = 144 cu. ft.

Compare the size of the closets

160 cu. ft. > 144 cu. ft.

Answer: The first closet is larger.

Both the can and the pan are cylindrical shapes. Compare the volumes of the two objects.

Volume of Can

V = πr2h

V = 3.14 × (1.5 in.)2 × 5 in.

V = 3.14 × 2.25 sq. in. × 5 in.

V = 35.325 cu. in.

Volume of Pan

V = πr2h

V = 3.14 × (4 in.)2 × 3 in.

V = 3.14 × 16 sq. in.× 3 in.

V = 150.72 cu. in.

35.325 cu. in. soup can < 150.72 cu. in pan

Answer: The volume of the soup can is less that that of the pan, so the soup will fit in the pan.

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