These 3 objects are used to make all of the other objects that we will use in geometry
Answer: -1/2
Step-by-step explanation:
Rise= 1
Run= 2
Answer:
187 ft/s
Step-by-step explanation:
Given in the y direction:
v₀ = 0 ft/s
Δy = 75 ft
a = 32 ft/s²
Find: t
Δy = v₀ t + ½ at²
(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²
t = 2.165 s
Given in the x direction:
Δx = 480 ft
a = 0 ft/s²
t = 2.165 s
Find: v₀
Δx = v₀ t + ½ at²
(480 ft) = v₀ (2.165 s) + ½ (32 ft/s²) (2.165 s)²
v₀ = 187 ft/s
Step-by-step explanation:
y is easy.
it is the Hypotenuse (baseline) of the small right-angled triangle created by the height (8) of the main triangle, the segment 6 of the main Hypotenuse and y.
so, Pythagoras :
y² = 8² + 6² = 64 + 36 = 100
y = 10
x is a bit more complex.
I think the easiest way to get it is to know that the height of a right-angled triangle to the Hypotenuse is the square root of the product of both segments of the Hypotenuse.
so, if we call the segments of the Hypotenuse a and b with a = 6, we have
x = a + b = 6 + b
height (8) = sqrt(a×b) = sqrt(6b)
therefore,
6b = height² = 8² = 64
b = 64/6 = 32/3 = 10 2/3 = 10.66666666...
so,
x = 6 + 10.66666... = 16.666666666...
round it to what is needed. e.g. 2 positions after the decimal point (hundredths) ? then it would be 10.67
9514 1404 393
Answer:
16 miles
Step-by-step explanation:
The problem can be modeled by a right triangle with one angle of 7° and the side opposite being 10,000 ft. The distance needed is the hypotenuse of the triangle, so the relevant trig relation is ...
Sin = Opposite/Hypotenuse
Hypotenuse = Opposite/Sin
air distance = (10,000 ft)/sin(7°) ≈ 82,055 ft
At 5,280 ft per mile, that is ...
(82,055 ft)/(5,280 ft/mi) ≈ 15.54 mi
The plane's air distance to the airport is about 16 miles.
