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cupoosta [38]
3 years ago
6

Why is the petrol price cheaper at coastal than inland

Mathematics
2 answers:
Daniel [21]3 years ago
5 0

Answer: If a litre of fuel at the coast (95 octane) costs R13,89, then 38% is tax. The difference between inland and coastal fuel prices is mainly due to transport costs of the fuel from depots at the coat to inland outlets.

kolezko [41]3 years ago
5 0
The petrol price is cheaper at coastal than inland due to the cost of transporting the petrol to inland. Deposits are found along the coast, so the price to transport the petrol is much cheaper than having to transport it all the way from the coast to inland. Therefore, transportation costs are the cause of petrol prices being cheaper at the coast than it is inland.
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Leokris [45]
Something is wrong here, the slope is off...

m=(y2-y1)/(x2-x1)

m=(1-3)/(12--4)

m=-2/16

m=-1/8

So the point slope form should be:

y-1=(-1/8)(x-12)

The standard form of the line is ax+by=c so we need to rearrange it to reflect the this form...multiply both sides by -8 to get:

8-8y=x-12  subtract 8 from both sides

-8y=x-20  subtract x from both sides

-x-8y=-20  by convention, the coefficient of x should be positive, multiply both sides by -1

x+8y=20

....

Just to show that the equation given you is incorrect..

y-1=(x-12)/4  using the point (-4,3)

3-1=(-4-12)/4

2=-16/4

2=-4  which is obviously incorrect...(they had the wrong slope for the two points given)
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4 years ago
What is an equation of the line that passes through the points (6, -7) and (-6, 3)?
Mars2501 [29]
Two point form:
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Nate and his sister Natalie are walking around the track at school and they’re walking at a steady rate. Nate walks 5 feet in 2
lutik1710 [3]
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10_4        4_4
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Natalie walked 6 feet
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tatyana61 [14]

Answer:

1.45

2.61

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Step-by-step explanation:

Use rule that a straight line is 180 and a right angle is 90

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3 years ago
Solve each inequality. Then compare the solutions.<br><br> 3x +4&gt; 16<br> - 2x + 19&lt; 11
Makovka662 [10]

Answer:

3x + 4 > 16 \\ 3x > 16 - 4 \\  \frac{3x}{3}  >  \frac{12}{3}  \\ x > 4 \\  \\  - 2x + 19 < 11 \\  - 2x < 11 - 19 \\  - 2x <  - 8 \\  \frac{ - 2x}{ - 2}  >   \frac{ - 8}{   - 2}  \\ x > 4 \\  \\ comparing \\ 4 < x > 4

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