<h3><u>Answer;</u></h3>
D. Longitudinal waves
<h3><u>Explanation;</u></h3>
- A wave is a transmission of a disturbance from one point to another. It involves the transmission of energy from a source to other points.
- <em><u>Waves may classified as longitudinal waves or transverse waves depending on the vibration of particles relative to the wave motion.</u></em>
- <em><u>Longitudinal waves are waves in which the vibration of particles is parallel to the direction of the wave motion, while transverse wave are types of waves in which the vibration of particles is perpendicular to the wave motion.</u></em>
- Longitudinal waves creates regions of compressions and rarefactions, while transverse waves creates regions of maximum displacement called crests and troughs
Answer:
14, 85 J
Explanation:
The formula of potential Energy (P.E.) is
P.E. = m * g * h, where m is the mass in kilograms, g is the acceleration due to gravity (about 10 m /
at the surface of the earth) and h is the height in meters.
Here P.E. is 0,55 kg * 10 m/s * 2,7 m = 14, 85 J
Answer:
Angular velocity of tire ![\approx 66.67\ s^{-1}](https://tex.z-dn.net/?f=%5Capprox%2066.67%5C%20s%5E%7B-1%7D)
Explanation:
Given:
Diameter of tire of an automobile =75.0 cm
Linear velocity of automobile = 90.0 km/hr
To find angular velocity of tire.
Diameter of tire in meters = ![75\ cm \times \frac{1\ m}{100\ cm}= 0.75\ m](https://tex.z-dn.net/?f=75%5C%20cm%20%5Ctimes%20%5Cfrac%7B1%5C%20m%7D%7B100%5C%20cm%7D%3D%200.75%5C%20m)
Radius of tire = ![\frac{1}{2}\times diameter=\frac{1}{2}\times 0.75\ m = 0.375\ m](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20diameter%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.75%5C%20m%20%3D%200.375%5C%20m)
Linear velocity in meters per second = ![\frac{90\ km}{1\ hr}\times \frac{1000\ m}{1\ km}\times \frac{1\ hr}{3600\ s}= 25\ m/s](https://tex.z-dn.net/?f=%5Cfrac%7B90%5C%20km%7D%7B1%5C%20hr%7D%5Ctimes%20%5Cfrac%7B1000%5C%20m%7D%7B1%5C%20km%7D%5Ctimes%20%5Cfrac%7B1%5C%20hr%7D%7B3600%5C%20s%7D%3D%2025%5C%20m%2Fs)
Angular velocity
is given by :
![\omega=\frac{v}{r}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bv%7D%7Br%7D)
where
represents linear velocity and
represents radius of tire.
Plugging in values.
![\omega=\frac{25\ m/s}{0.375\ m}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B25%5C%20m%2Fs%7D%7B0.375%5C%20m%7D)
∴
(Answer)
Answer:
If the net force on an object is zero, the momentum of the object will not change
Explanation: If the net force on an object is zero, the momentum of the object will not change. If a non-zero net force acts on the object, the magnitude of its momentum could decrease, increase, or remain constant