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3 years ago

Instantaneous speed is measured

Physics

1 answer:

torisob [31]3 years ago

6 0

By using a tangent line.

I need a bit more info to be sure but that's not wrong.

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Plz help

slamgirl [31]

Answer:

Force,friction,inertia and momentum

Explanation:

The speed that the marble is moving at can be determined by the amount of force used when pushed or pulled and what kind of surface it's on.Momentum is also a factor because of the mass of the marbles.

6 0

3 years ago

At what latitudd is the coriolis effect the smallest

alexandr1967 [171]

The Coriolis effect is strongest at the north and south poles, and zero on the equator (zero latitude).

6 0

4 years ago

Renald completed only one trial of his experiment. what effect will this most likely have?

Tatiana [17]

Remember the rule of thumb that every person learns in Elementary Science? You must do multiple experiments in order to get to a conclusion. In order for a conclusion to be valid you must test the conclusion multiple times. You wouldn't want a doctor to just test an aspirin 1 time on 1 patient and say yes it works correct? No, you would want him/her to test on multiple patients in multiple settings and conditions so that when you take an aspirin you know that it will work for what you are taking it for. So ..... with all that being said.....Your answer is (A). The results are more likely to have errors.

6 0

3 years ago

An optical disk drive in a computer can spin a disk at up to 10,000 rpm. If a particular disk is spun at 7570 rpm while it is be

anastassius [24]

Answer:

The magnitude of the average angular acceleration is calculated as $1822.36\ rad/s^{2}$

Explanation:

Maximum speed that can be attained by the disk, $N_{m}$ = 10,000 rpm

Speed of spinning of the disk, N = 7570 rpm

Time taken to come to rest, t = 0.435 s

Now,

The initial angular velocity is given by:

$\omega = \frac{2\pi N}{60} = 792.73\ rads^{-1}$

Final angular velocity, $\omega' = 0\ rads^{- 1}$

The average angular acceleration of the disk can be computed by using the kinematic eqn:

$\omega' = \omega + \alpha t$

$0 = 792.73 + 0.435\alpha$

$\alpha = - 1822.36\ rads^{- 2}$

5 0

4 years ago

Read 2 more answers

In a perfectly elastic collision between two perfectly rigid objects

ipn [44]

Both the total momentum and the total kinetic energy are conserved

Explanation:

- In a collision between two or more objects, if there are no external forces acting on the system (isolated system), the total momentum of the objects is always conserved. This is called principle of conservation of momentum, and can be written as follows:

$mu+MU = mv+MV$

where

m, M are the masses of the two objects

u, U are the initial velocities of the two objects

v, V are the final velocities of the two objects

- The total kinetic energy, however, is not always conserved. In fact, we have two types of collision:

1) In a perfectly elastic collision, the total kinetic energy of the objects is conserved. This means that we can write the following equation:

$\frac{1}{2}mu^2 + \frac{1}{2}MU^2 = \frac{1}{2}mv^2+\frac{1}{2}MV^2$

2) In an inelastic collision, the total kinetic energy of the object is NOT conserved. This means that part of the total kinetic energy is "lost", converted into other forms of energy (mainly thermal energy, due to the presence of frictional forces within the system). The most extreme case is called perfectly inelastic collision, in which the two objects stick together after the collision, and there is the maximum loss of kinetic energy.

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

LearnwithBrainly

7 0

4 years ago