Explanation:
It is given that,
Force on grindstone, F = 180 N
Radius of grindstone, r = 0.28 m
Mass of grindstone, m = 75 kg
We need to find the angular acceleration of the grindstone. In rotational motion, the relation between the torque and angular acceleration is given by :
I is the moment of inertia of solid disk,
is the torque exerted,
So, the angular acceleration of the disk is . Hence, this is the required solution.
Answer:
N₂ = 503.8 N
Explanation:
given,
mass of bottom block = 37 Kg
mass of middle block = 18 Kg
mass of the top block = 16 Kg
force acting on the top block = 170 N
force on the block at top
N₁ be the normal force from block at middle
now,
N₁ = 170 + m g
N₁ = 170 + 16 x 9.8
now, force on block at middle
N₂ be the normal force exerted by the bottom block
N₂ = N₁ + m₂ g
N₂ = 326.8 + 18 x 9.8
N₂ = 503.8 N
hence, normal force by bottom block is equal to N₂ = 503.8 N
Basic is the answer. (i think so)
I = V / R
Current = (voltage) / (resistance)
Current = (500 V) / (250 ohms)
Current = (500/250) Amperes
<em>Current = 2 Amperes</em>