Most meteor showers are associated with the orbits of
2 answers:
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<u>We are given:</u>
Direction of motion: 25 degrees south of the east axis
Distance covered = 125 m
<u>East component of the Ball:</u>
<em>this component is denoted by green color in the image</em>
Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle
The magnitude of the side of the triangle on the x-axis denotes the east component of the ball
Using trigonometry, we find that the east component of the ball is:
125 * Cos(25 degrees)
125 * 0.9 = 112.5 i (here, i denotes rightward direction on the x-axis)
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<u>North Component of the Ball:</u>
<em>this component is denoted by blue color in the image</em>
Using trigonometry, we find that the North component of the ball is:
125* Sin(25 degrees) (-j) <em>[j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']</em>
125 * 0.42 (-j)
52.5 (-j) = -52.5 j
Therefore the direction vector of the ball is 112.5 i - 52.5 j
<em>where 112.5 i is the East Component and -52.5 is the North Component</em>
