Answer:
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
= -5 = -2x + 15
Step-by-step explanation:
Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5).
Using the slope intercept equation,
y = mx +c
m = slope = 1/2
For two lines to be perpendicular, the product of their slopes is -1
Let the slope of the other line be m2
m1×m2 =-1
1/2×m2 = -1
m2 = -1/(1/2) = -2
Slope of line = -2
For points (10, -5), x = 10, y =-5
-5 = -2× 10 +c
-5 = -20+ c
c = -5+20= 15
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
-5 = -2x + 15
Answer:
Slope is 1/2
Step-by-step explanation:
Use the slope formula. Say S = the 1st point and T = the 2nd point.
m = 20 - 10 10 1
------------ = ----------- = ---
20 - 0 20 2
The equation for slope is also y = mx + b
m is the slope, b is the y-intercept.
Therefore, if you look at the 1st choice, you can see that 1/2 is in the place of m, meaning that 1/2 is the slope of line ST
I dunno how to do the other way
Answer:
x > 24
Step-by-step explanation:
12 + 12 = 24
So the function we're dealing with is
f(x) =
Factorising we get,
Therefore, the vertical asymptotes are at x = 3 and x = 6
Answer
an=a1+(n-1)d
Step-by-step explanation:
a2-a=9_2=7
a3-a2=16-9=7
a4-a3=23-16=7
a5-a4=30-23=7
