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2 years ago

10

How do you solve

\div 4 = " align="absmiddle" class="latex-formula">
923÷4

1 answer:

IgorC [24]2 years ago

8 0

230.75 hope this helps :)

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Find 72% of 50<br>(REEEEEE)

Snowcat [4.5K]

Answer:

The answer is 37.44

Step-by-step explanation:

Step 1: Divide 52 by 100

In this case, the number that we are "comparing" to 100 is 52, so we must first normalize the number by dividing it by 100. The operation we have to solve is this:

52

100

=

52

÷

100

=

0.52

Step 2: Multiply 0.52 by 72 to get the solution

Now that we have our normalized number, 0.52, we just have to multiply it by 72 to get our final answer. The forumla for this is obviously quite simple:

0.52

×

72

=

37.44

8 0

3 years ago

GOOD AT GEOMETRY??? NEED BRAINLIEST AND POINTS?? YOU NEED MY HELP AND I NEED YOURS! ALL YOUR HELP IS APPRECIATED!!!

jeyben [28]

Answer:

<h2>In a quadrilateral, opposite angles are congruent.</h2>

Step-by-step explanation:

Angle B & D are both opposite to each other, yet congruent.

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3 years ago

Karl has $400 in a savings account. The interest rate is 10%, compounded annually. Which type of model best fits this situation?

n200080 [17]

Answer:

He prolly only got like 300 some left

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

Kelsey graphed the equation y = 3x + 1 as shown below.

USPshnik [31]

Answer:

D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.

Step-by-step explanation:

The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1

However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;

m=Δy/Δx where

m=the slope of the graph

Δy= 3-0 =3

Δx= 0--3 =3

m=3/3 = 1

The equation of the line should be;

m=Δy/Δx

1=y-3/x-0

1x= y-3

3+1x= y

y= 1x + 3 ----------where the slope is 1 and y-intercept is 3

So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>

While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>

<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>

Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.

Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3

Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.

4 0

3 years ago

Read 2 more answers