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german
3 years ago
12

Can somebody please solve question 11?

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0
1+tan^2=sec^2
so, given expression= \frac{sec^{2}*cot}{cosec^{2} } = \frac{ \frac{1*cot}{ cos^{2} } }{ \frac{1}{ sin^{2} } } =tan^{2}*cot = tan 
(using sin/cos=tan and tan*cot=1)

hence proved
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If a cross-country runner runs a 55 kilometer (km) race, how many miles is that? Round your answer to one decimal place.
prohojiy [21]

Answer: 34.2

For everyone 1 kilometer=.621371 so if you times that by 55 you get 34.1754 which rounds to 34.2

5 0
3 years ago
6. Santiago Diaz Granados played an arcade game that cost 25 tokens per game. In six games, Santiago won 0 tokens, 10 tokens, 50
Pavel [41]
-- To play the six games, <span>Santiago Diaz Granados spent

                                             (6 x 25) = 150 tokens.

-- As a result of his skill, experience, talent, steady hand, nerves
of steel, superior hand-eye coordination, and superb reflexes, </span><span>
Santiago Diaz Granados won</span>

                 (0 + 10 + 50 + 0 + 5 + 10) = 75 tokens.

-- At the end of the 6th game, <span>Santiago Diaz Granados was behind
the curve. 
After spending 150 tokens and winning 75 tokens, </span><span>Santiago Diaz Granados
was down by (150 - 75) = 75 tokens since he arrived at the arcade. 
Any true friend could look at the choices, could see that choice-B is
the correct one, and could advise </span><span>Santiago Diaz Granados to cash in
whatever he had left, accept his losses, return to his home, and live
to fight another day. 

Viva </span><span>Santiago Diaz Granados ... </span><span>un verdadero héroe de su pueblo.  Viva !</span>
3 0
3 years ago
How long can I talk on the phone if they charge 8 cent a minute and I have 90 cents
NeTakaya
U can talk only for 11 minutes and have 2cents left
6 0
3 years ago
Read 2 more answers
What is the equation in point slope form of the line that is perpendicular to the given line and passes through the point -4, -3
Maurinko [17]

Answer:

y=x^2+7x+12

Step-by-step explanation:

4 0
3 years ago
Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
4 years ago
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