6/25 - 4/5.......u should choose the lowest common denominator which is 25.
6/25 - 20/25 = - 14/25
however, even if u didn't pick the lowest....lets say u picked 50
6/25 - 4/5 = 12/50 - 40/50 = - 28/50 reduces to - 14/25...u will still get the same answer...u will just have to reduce
the reason u want to pick the lowest common denominator is because it is easier....if u do not pick the lowest, u will have to reduce....so picking the lowest just saves you time. also u can round up or down if u wanna be more smart
Answer:
<em>The true statements are:</em>
<em>*The median weight for shelter A is greater than shelter B.</em>
<em>*The (IQR) interquartile range of shelter A is greater than the (IQR) interquartile range of shelter B.</em>
Step-by-step explanation:
<em>(for shelter A)</em>
median: 21
lowest value: 8
highest value: 30
lower quartile: 17
upper quartile: 28
(IQR) interquartile range: 28 - 17 = 11
Range: 30 - 8 = 22
<em>(for shelter B)</em>
median: 18
lowest value: 10
highest value: 28
lower quartile: 16
upper quartile: 20
(IQR) interquartile range: 20 - 16 = 4
Range: 28 - 10 = 18
~phew!, this took me long xd, hope this helps you~
I would highly appreciate it if you would mark me the brainliest~ :)
<u>Part 1)</u> A 20° sector in a circle has an area of 21.5π yd².
What is the area of the circle?
we know that
the area of a circle represent a sector of
degrees
so by proportion
therefore
<u>the answer part 1) is</u>
The area of the circle is ![1,215.18\ yd^{2}](https://tex.z-dn.net/?f=1%2C215.18%5C%20yd%5E%7B2%7D)
<u>Part 2)</u> What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?
we know that
the area of the circle is equal to
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
where
r is the radius of the circle
in this problem we have
![Diameter=21.2\ cm\\ r=Diameter/2\\r=21.2/2\\r= 10.6\ cm](https://tex.z-dn.net/?f=Diameter%3D21.2%5C%20cm%5C%5C%20r%3DDiameter%2F2%5C%5Cr%3D21.2%2F2%5C%5Cr%3D%2010.6%5C%20cm)
<u>Find the area of the circle</u>
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
![A=\pi*10.6^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%2A10.6%5E%7B2%7D)
![A=352.8104\ cm^{2}](https://tex.z-dn.net/?f=A%3D352.8104%5C%20cm%5E%7B2%7D)
<u>Find the area of the sector</u>
we know that the area of the circle represent a sector of
radians
by proportion
therefore
<u>the answer part 2) is</u>
the area of the sector is
![105.84\ cm^{2}](https://tex.z-dn.net/?f=105.84%5C%20cm%5E%7B2%7D)