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Inga [223]
3 years ago
8

If, instead of the second electron coming in from infinity, it is initially at x = + 20.00 m on the axis and is given an initial

velocity of 500.0 m/s toward the origin, does it reach the origin?
Mathematics
1 answer:
Brut [27]3 years ago
6 0

Answer:

If the electron keeps that speed, then yes.

Step-by-step explanation:

The electron is given an initial position in the space, and is given a positive velocity and a direction towards the origin. Since the distance is finite, eventually, by keeping the same velocity and direction it will reach the origin At some time.

If the speed gradually decreases, it may be the case that the particle will never reach the origin (even though it may never stop), but since the problem doesnt state anything i am assuming that is not the case.

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Can someone help me understand the concept of finding the domain and range on a graph. I don’t understand it! Someone help me
juin [17]

Answer:

The Domain is where the line on your graph crosses the X axis.

The Range us where the line on your graph crosses the Y axis

And a arrow means it goes Into infinity

Step-by-step explanation:

Say you Have a line, it crosses the X axis at -3, your Domain would be -3!

Now say this line crosses the Y axis at -6, Your Range would be -6!

And now say if instead of the line ending at a dot after crossing -6 It has a arrow, that means you have infinity, Making your range instead of -6 it's be infinity! (If the arrow points up it's positive infinity, If the arrow points down it's negative infinity)

So for the first 2 numbers your answer would be [-3,-6] and in you have infinity itd be [-3, infinity) parenthesis isn't a error btw if you still don't get it I can just reply with a sheet I have on it

5 0
3 years ago
the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)
oksano4ka [1.4K]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
%  (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9
6 0
3 years ago
Brainist to who answers this! ​
yanalaym [24]

Answer:

13t² + 2t + 9

Step-by-step explanation:

(9t² - 3t + 5) - (-4t² + 5t + 4)

Solving like terms

-(-4t²) becomes + 4t²

(9t² + 4t²) + (-3t + 5t) + (5+4) =

13t² + 2t + 9

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
3 years ago
Read 2 more answers
Write the equation of the line that is perpendicular to the graph of 2x+y =5, and y-intercept is 4.
Sophie [7]
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7 0
3 years ago
you make a scale drawing of a banner for school dance .you use a scale of 1 inch ,2 feet what is the actual width of the banner
sashaice [31]

Answer:

6.5

Step-by-step explanation:

you take the sides all added up (which was 13in) and divided it by two

5 0
3 years ago
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