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user100 [1]
2 years ago
8

Please help me this is so confusing to me.

Mathematics
1 answer:
Naddik [55]2 years ago
8 0

Hi there! :)

\large\boxed{A = 120^{o}}

Find the central angle using a ratio in regards to angle and circumference.

The radius is 27 units, so use the following equation to calculate circumference:

C = 2rπ

Therefore:

C = 2(27)π = 54π

Since we have the total circumference, we can write the following proportion:

\frac{x}{360} = \frac{18\pi}{54\pi}

Cross multiply:

54πx = 6480π

Divide both sides by 54π to isolate for x:

x = 120°

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Norma-Jean [14]

Answer:

O 14

Step-by-step explanation:

hope it is helpful :)

7 0
2 years ago
What is the period of the function y = 2 sinx
DanielleElmas [232]

Answer:

The period is 360° ( in radians, the period is 2π)

Step-by-step explanation:

For a sine/cosine (sinusoidal) function in the form

y = ASin(Bx-C) + D, we can say

A is the amplitude

360/B is the period

C is the phase shift

D is the vertical translation

<em>The function given is y = 2Sinx</em>

To find the period, we need 360/B. Since "B" is just "1", the period is

360/1 = 360

5 0
2 years ago
Read 2 more answers
express 121,200 in exponential (powers of 10) notation. express the earth sun distance in kilometers in powers of 10 notation.
Mashutka [201]

The exponential form of given number 121200 is 1.212 × 10^5

And the earth sun distance in kilometers in powers of 10 notation is 1.5 × 10^8

For given question,

We need to express 121,200 in exponential (powers of 10) notation.

To use scientific notation, pick a value between 1 and 10, then multiply it by 10ˣ.

The number between 1 and 10 in 121200 is 1.212 with 5 decimal points.

So, the exponential notation of given number would be,

121,200 = 1.212 × 10^5

Earth's average distance from the Sun is around 93 million miles (150 million kilometers). That's one AU.

So the number between 1 and 10 in 150,000,000 is 1.5, with 8 decimal points.

So, the distance between he Earth and the Sun is:

150,000,000 = 1.5 × 10⁸

Therefore, the exponential form of given number 121200 is 1.212 × 10^5

And the earth sun distance in kilometers in powers of 10 notation is 1.5 × 10^8

Learn more about the powers of 10 here:

brainly.com/question/13303295

#SPJ4

4 0
1 year ago
Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

3 0
3 years ago
What is the gcf In this problem
Sergeeva-Olga [200]
The GCF of 88r^{18} \; 24r^{13} would be 8r^{13}
6 0
3 years ago
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