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3 years ago

Please help me this is so confusing to me.

Mathematics

1 answer:

Naddik [55]3 years ago

8 0

Hi there! :)

$\large\boxed{A = 120^{o}}$

Find the central angle using a ratio in regards to angle and circumference.

The radius is 27 units, so use the following equation to calculate circumference:

C = 2rπ

Therefore:

C = 2(27)π = 54π

Since we have the total circumference, we can write the following proportion:

$\frac{x}{360} = \frac{18\pi}{54\pi}$

Cross multiply:

54πx = 6480π

Divide both sides by 54π to isolate for x:

x = 120°

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Two cars are on the same straight road. Car A moves east at 55 mph and sounds its horn at 625 Hz. Rank from highest to lowest th

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Step-by-step explanation:

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3 years ago

The number of applicants to a university last year was 11,450. This year, the number of applicants grew by 2%. How many applican

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3 years ago

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An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

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3 years ago

Simplify the following expression. 7^-5/6.7^-7/6. 1/49 1/14 14 49

Serggg [28]

${7}^{ - \frac{5}{6} } \times {7}^{ - \frac{7}{6} } \\ = {7}^{ - \frac{5}{6} - \frac{7}{6} } \\ = {7}^{ - \frac{12}{6} } \\ = {7}^{ - 2} \\ = \frac{1}{ {7}^{2} } \\ = \frac{1}{49}$
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