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tatyana61 [14]
3 years ago
13

PLEASE HELP How can you use simulations to determine the probability of events?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

Describe the possible outcomes.

Link each outcome to one or more random numbers.

Choose a source of random numbers.

Choose a random number.

Based on the random number, note the "simulated" outcome.

Repeat steps 4 and 5 multiple times; preferably, until the outcomes show a stable pattern.

Step-by-step explanation: i honestly don't know i got this off of the gooooogle :D

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If two fair dice are tossed, what is the smallest number of throws, n, for which the probability of getting at least one double
amid [387]

This is a rather famous probability problem.

The easiest way to solve this is to calculate the probability that you WON'T roll a "double 6" (or a twelve) each time you roll the dice.  There are 36 ways in which dice rols can appear and only one is a twelve.  So, for one roll, the probability that you will NOT get a twelve is (35/36)^n where 35/36 is about .97222222 and n would equal 1 for the first trial.  So for your first roll the odds that you WON'T get a 12 is .97222222.

For the second roll we calculate (35/36) to the second power or (35/36)^2 which equals about .945216.

When we get to the 24th roll we calculate (.97222222)^24 which equals 0.508596.  

For the 25th roll, we calculate (.97222222)^25 which equals  0.494468.  For the first time we have reached a probability which is lower than 50 per cent.  That is to say, after 25 rolls, we have reached a point in which the probability is less than 50 per cent that we will NOT roll a twelve.

To phrase this more clearly, after 25 rolls we reach a point where the probability is greater then 50 per cent that you will roll a 12 at least once.

Please go to this page 1728.com/puzzle3.htm and look at puzzle 48. (The last puzzle on the page).  An intersting story associated with this probability problem is that in 1952, a gambler named Fat the Butch bet someone $1,000 that he could roll a 12 after 21 throws.  (He miscalculated the odds [as we know you need 25 throws] and after several HOURS, he lost $49,000!!!)

Please go that page and it has a link to the Fat the Butch story.


3 0
3 years ago
3. A pattern of growth with a constant value added is ________________________________ .
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6 0
3 years ago
Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN.
shtirl [24]
Given that <span>point L is between M and N on MN. Then
MN = ML + LN
31 = h - 15 + 2h - 8 = 3h - 23
3h = 31 + 23 = 54
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Therefore, LN = 2(18) - 8 = 36 - 8 = 28.
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8 0
3 years ago
I will mark you brainiest if you an answer this
irinina [24]

Answer:

the awnswer is a = 7 + c

Step-by-step explanation:

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