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2 years ago

Ben is travelling home to Birmingham on the M1 and M42. Both motorways have road works.

1 answer:

8 0

In the question "Ben is travelling home to Birmingham on the M1 and M42. Both motorways have road works. He has a fifty-fifty chance of getting delayed on the M42 and a 75% chance of being delayed on the M1. What are the chances that he will not be delayed on his journey?" The chance that he will not be delayed in his journey is the chance that he will not be delayed on the M1 and he will not be delayed on the M42. Probability of getting delayed on the M1 = 75% = 0.75 Probability of not being delayed on the M1 = 1 - 0.75 = 0.25 Probability of getting delayed on the M42 = 50% = 0.5 Probability of not being delayed on the M42 = 1 - 0.5 = 0.5 Probability of not being delayed on the M1 and not being delayed on the M42 = 0.25 x 0.5 = 0.125 = 1 in 8

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Step-by-step explanation:

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3 years ago

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2 years ago

Read 2 more answers

The perimeter of a rectangle is 72 cm. The length is 3 more than twice the width What

solmaris [256]

<h3>Solution</h3>

Given :-

Perimeter of rectangle = 72 cm
The length is 3 more than twice the width.

Find :-

Dimensions of rectangle

<h3 /><h3>Explantion</h3>

Using Formula

$\boxed{\underline{\tt{\red{\:(perimeter_{rectang}\:=\:2\times (Length+Width)}}}}$

Let,

Length of Rectangle = x cm
Breadth of Rectangle = y cm

According to question,

==> perimeter of Rectangle = 72

==> 2(x+y) = 72

==> x + y = 72/2

==> x + y = 36_________________(1)

Again,

==> x = 2y + 3

==> x - 2y = 3__________________(2)

Subtract equ(1) & equ(2)

==> y + 2y = 36 - 3

==> 3y = 33

==> y = 33/3

==> y = 11

keep in equ(1)

==> x - 2×11 = 3

==> x = 3 + 22

==> x = 25

<h3>Hence</h3>

Length of Rectangle = 25 cm
Width of Rectangle = 11 cm

<h3 />

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Step-by-step explanation:

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2 years ago

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Oksana_A [137]

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2 years ago