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3 years ago

Fernando will divide 0.24 by 4 to help him solve a math problem. Which model below could represent this math problem

Mathematics

1 answer:

balandron [24]3 years ago

6 0

Answer:

So the model should represent either $\frac{6}{100}$ or $\frac{3}{50}$ (its equivalent and simplified form.

Step-by-step explanation:

1) Originally the question wants to represent this quotient as tiles.

So, $\frac{\frac{24}{100}}{4} =\frac{24}{100} *\frac{1}{4} =\frac{6}{100}=$

We can still simplify it, but since we're dealing with 100 x 100 squares let's keep it this way

2) So the model should represent either $\frac{6}{100}$ or $\frac{3}{50}$ (its equivalent and simplified form.

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3 years ago

Simplify expression 2g +3(g+5)

Sophie [7]

Answer:

$5g+15$

Step-by-step explanation:

To solve this question, we will first expand the expression using the distributive rule: $x(y+z)=xy+xz$

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4 years ago

Read 2 more answers

If | 8x -2 | < 4, Which of the following is true of x? Explain as well.

wariber [46]

The true expression of the variable x in the inequality expression given as |8x - 2| < 4 is -0.25 < x < 0.75

<h3>What are inequality expressions?</h3>

Inequality expressions are mathematical statements that are represented by variables, coefficients and operators where the opposite sides are not equal

<h3>How to determine the true expression of the variable x?</h3>

The inequality expression is given as

|8x - 2| < 4

Divide through the above equations by 2

So, we have the following inequality expression

|4x - 1| < 2

Remove the absolute value sign from the inequality expression

So, we have

-2 < 4x - 1 < 2

Add 1 to all sides of the above inequality expression

So, we have

-1 < 4x < 3

Divide through the above inequality expression by 4

So, we have

-0.25 < x < 0.75

Hence, the true expression of the variable x in the inequality expression given as |8x - 2| < 4 is -0.25 < x < 0.75

Read more about inequality at

brainly.com/question/25275758

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1 year ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$