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Semmy [17]
3 years ago
5

PLEASE HELP DON'T ANSWER UNTIL I POST THE SCREENSHOT

Mathematics
2 answers:
dedylja [7]3 years ago
8 0
Here is your answer:

The Y axis is the line going straight down since is negative you go down 2 times

Which makes it y=-2 or A.
IgorLugansk [536]3 years ago
6 0
The answer is y=2, because the line passes through the point (-2,2).
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1. John and Carolyn are planning a picnic for some of their friends. In all there will be 28 people. They plan to barbecue steak
Sonja [21]

1. 28 x 3/4 = 21 kg

2. 1 hr = 60 mins

=》 1/4 hr = 60/4 = 15mins

4 0
3 years ago
Read 2 more answers
Find the amount of time. <br> 8. I = $2000, P = $5000, r = 8%
algol [13]

Answer:

t = 5 years

Step-by-step explanation:

I = $ 2000

P = $ 5000

r = 8%

I = P * \frac{r}{100}*t\\\\t =\frac{ I * 100}{P*r}\\\\t =\frac{2000*100}{5000*8}\\\\ = 5

5 0
3 years ago
Solve for x each is a parallelogram
jonny [76]

Answer:

UW = EW+UE=2×EW because, EW=UE

7x-2=2×6= 12

7x=14

x=14/7

x=2

<h2>2 is the right answer.</h2>

x + 80 = 180 - (64 + 36)

x + 80 = 180 - 100

x + 80 = 80

x = 0

<h2>0 is the right answer.</h2>
3 0
3 years ago
In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.
Sveta_85 [38]

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\dfrac{\text{Opposite leg}}{\text{Hypotenuse}}=\dfrac{MN}{MP}\\ \\MN=MP\sin \angle P\\ \\MN=4\sin 21^{\circ}\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}=\dfrac{MH}{MN}\\ \\MH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^{\circ}-m\angle P=90^{\circ}-21^{\circ}=69^{\circ}

Thus,

MH=1.43\cos 69^{\circ}\approx 0.51\ cm

7 0
3 years ago
WILL AWARD BRAINLIEST
MAVERICK [17]

Answer:

ΔABC ~ ΔDEC

Step-by-step explanation:

Given : DE║AB

              Statements                              Reasons

1). DE║AB                                              1). Given

2). ∠CDE ≅ ∠CAB                                2). Corresponding angles

                                                [Since DE║AB and AC is the transverse]

3). ∠CED ≅ ∠CBA                                3). Corresponding angles

                                                [Since DE║AB and BC is the transverse]

4). ΔABC ~ ΔDEC                                 4). By AA property of similarity    

Hence ΔABC is similar to ΔDEC.

6 0
3 years ago
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