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navik [9.2K]
3 years ago
9

Verizon charges a $40 sign-up fee and the $60 a month for their new hotspot. T-Mobile

Mathematics
2 answers:
o-na [289]3 years ago
8 0

Step-by-step explanation:

Start Unlimited: 

$70 for one line

$60 for two lines

$45 for three lines

$35 for four lines

Play More Unlimited: 

$80 for one line

$70 for two lines

$55 for three lines

$45 for four lines

Do More Unlimited: 

$80 for one line

$70 for two lines

$55 for three lines

$45 for four lines

Get More Unlimited: 

$90 for one line

$80 for two lines

$65 for three lines

$55 for four lines

Andrei [34K]3 years ago
3 0

Answer:

4 months

As we show that ;

40 + (60x * 4)  = 280

100 + (45x * 4) = 280

but in simultaneous equations Verizon must be set equal to 240 being 80 x 3

and T mobile must be equal to 45 x 4 = 180

so that 240+ 180 = 420 to find 4

This would be a method on distribution as "60 sign up is 1/3 more than 1st equation.

Step-by-step explanation:

This is a simultaneous equation but trial and error is below to prove all is true.

step 1 make all equations same

40s + (60x)      * 3 = 180x  LCM   = 80 x 3   =  1   1/3 of 60

100s + (45x)     * 4 = 180x LCM   = 45  x 4   =  1 of 45 as verizon charges 1/3 more sign up.

100s- 40s + 180x = (180x) =  240 + 180

60s + 180x = 420

s = 60

so our equations must each end with 420

when we get 60s + 180x = 420  then

420 - 180 = 240

240/60 =  4

x = 4 months

Verizon = 1st and T mobile = 2nd

40 + (60x * 5)  = 340

100 + 45x * 5 = 325

with $15 out after 5 months so we try 6 months

40 + (60x * 6)  = 400

100 + 45x * 6 = 370

and see this is increasing in difference, so try a smaller value of months..

We try 4 months;

40 + (60x * 4)  = 280

100 + (45x * 4) = 280

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I hope this helps you



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\rightarrow\sf((p(x) {x}^{2}  + 2x + 4)( {x}^{2}  + 2x + 4)) \\  = \sf  {ax}^{2}  + bx + c \\  = \sf(p(x) {x}^{2}  {x}^{2}  + p(x) {x}^{2} (2x) + p(x) {x}^{2}  \times 4 + 2x \times  {x}^{2}  + 2x(2x) + 2x \times 4 +  {4x}^{2}  + 4(2x) + 4 \times 4) \\  = \sf( {x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16) \\   \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

<h3>Answer:</h3>

\large\boxed{\sf{\red{{x}^{4} p(x) +  {2x}^{3} p(x) +  {4x}^{2} p(x) +  {2x}^{3}  +  {8x}^{2}  + 16x + 16}}}

\color{red}{==========================}

✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

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✍︎ꕥᴋɪᴍ ᴀʀᴀꕥ

5 0
2 years ago
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