We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
41
Step-by-step explanation:
edge
You can either make a table using any numbers you would like (I would suggest -5 to 5) and then graphing the rule
ex. (7/2)(-5)-2 = -19.5 (I multiplied (7/2) by -5 and then subtracted 2)
Or you can put the rule in a graphing calculator and check the points from there
Answer:
0
Step-by-step explanation:
0 is what i got
<span>its C. Alan has 13 CDs, Tom has 16 CDs, Barbara has 23 CDs !</span>