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3 years ago

9

Evaluate x/y + 5 w^2, for x = 2/3 and y = 5/6, and w = 3

1 answer:

tresset_1 [31]3 years ago

5 0

2/3 / 5/6 + 5 (3)^2

= 2/3 * 6/5 + 45

= 12/15 + 45

= 45 4/5 Answer

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Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.

dalvyx [7]

Answer:

The measure of the side $QR$ is 8.8.

Step-by-step explanation:

Since $LMNO \sim PQRS$ , then $SP \propto OL$ , $RS \propto ON$ , $RQ \propto MN$ and $QP \propto LM$ . From figure we have the following relationship:

$k = \frac{OL}{SP} = \frac{ON}{RS} = \frac{MN}{QR} = \frac{ML}{QP}$ (1)

Where $k$ is the proportionality ratio.

If we know that $SP = 13, OL = 55, MN = 37$ , then the measure of side $QR$ is:

$k = \frac{OL}{SP}$ (1b)

$k = \frac{55}{13}$

$k = \frac{MN}{QR}$

$QR = \frac{MN}{k}$ (1c)

$QR = \frac{37}{\frac{55}{13} }$

$QR = 8.745$

The measure of the side $QR$ is 8.8.

4 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

Use a table of values to estimate the value of the limit. Confirm your result graphically by graphing the function with a graphi

il63 [147K]

Hello,

$\lim_{x \to 0}\dfrac{ \sqrt{x+25}-5}{x}\\\\$

$=\lim_{x \to 0}\dfrac{(\sqrt{x+25}-5)*(\sqrt{x+25}+5)}{x*(\sqrt{x+25}+5)}\\\\$

$=\lim_{x \to 0}\dfrac{x+25-25)}{x*(\sqrt{x+25}+5)}\\\\$

$=\dfrac{1}{10}$

4 0

3 years ago

I will mark brainliest!

Harrizon [31]

Answer:

a + 56.75 = 76.75

Step-by-step explanation:

that is because ,money raised on first day(a) + money raised on second day = 76.75

that gives us, a = $20

3 0

3 years ago

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Fractions greater than 1

hammer [34]

There is unlimited possibility’s to that question

4 0

3 years ago

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