You multiply the 2 together 4 5/6 and 2 2/3.
4 5/6=29/6
2 2/3=8/3
you multiply the tops together then the bottoms together
29*8=232
3*6=18
232/18=116/9
If 2 1/2 posterboard is enough for 1/2 of the project, it will take another 2 1/2 posterboard to display the other half of the project.
2 1/2 + 2 1/2 = 4 + 1/2 + 1/2 = 4 + 1 = 5
Answer: 5 posterboard.
Answer:
(B) Time (min) 2 , 3 , 7 , 9
Temperature (°C) 60.6 , 64.3 , 79.1 , 86.5
Step-by-step explanation:
The rate of change is found by using the formula for slope:

For option A, this gives us
m =(64.4-61.0)/(3-2) = 3.4/1 = 3.4
This is not more than relationship A.
For option B, we have
(64.3-60.6)/(3-2) = 3.7/1 = 3.7
This is more than relationship A.
For option C, we have
(65.3-61.8)/(3-2) = 3.5/1 = 3.5
This is not more than relationship A.
For option D, we have
(64.6-61.0)/(3-2) = 3.6/1 = 3.6
This is not more than relationship A.
They would be identical so it would be 114
Splitting up the interval of integration into
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length
. The right endpoints of each subinterval follow the sequence

with
. Then the left-endpoint Riemann sum that approximates the definite integral is

and taking the limit as
gives the area exactly. We have
