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juin [17]
3 years ago
9

A gate is made up of a rectangle and has a height of 6ft find the area of the gate

Mathematics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer: The area is 18ft

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7.48331477355

Step-by-step explanation:

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What is 2/3 equivalent to?
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Find the Prime Factorization of -165
Ghella [55]

Answer:

(-1)(11)(3)(5)

Step-by-step explanation:

First off:  -165 separates into the factors (-1) and (165).  Next, we divide 165 by 15, obtaining 15(11).

So far, we have (-1)(11)(15).

15 is still factorable.  We get:

(-1)(11)(3)(5), which is the desired prime factorization of -165.

6 0
3 years ago
A rancher has 4 comma 700 feet of fencing available to enclose a rectangular area bordering a river. he wants to separate his co
guapka [62]
Area=length*width
let the sides perpendicular to the river be x
then  the side parallel to the river is 4,700-2x 
A(x)=x(4700-2x)
A(x)=4700x-2x^2

This a quadratic function with a=-2 and b=4700
thus
Maximum area occurs where x=-b/2a=-4700(-2*2)=1,175 ft
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4 0
3 years ago
Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce
34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)

= 1 - P(z \leq -2)

Calculation the value from standard normal z table, we have,  

P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < 23.7) =0.159= 15.9\%

15.9% of of the boxes weigh less than 23.7 ounces.

7 0
3 years ago
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