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patriot [66]
3 years ago
8

The wind is blowing N 35.0 degrees W at 1.60 * 10^2 mph. A plane has an engine speed of 3.20 * 10^2 mph. Where should the pilot

point the plane in order to fly straight W?

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer: 24.2° SouthWest

<u>Step-by-step explanation:</u>

First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>

I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.

<u>Perpendicular (x):</u>

 cos 35° = adjacent/hypotenuse

  cos 35° = x/160

→ x = 160 cos 35°

<u>Angle (θ):</u>

sin θ = opposite/hypotenuse

sin θ = x/320

sin θ = 160 cos 35°/320

    θ = arcsin (160 cos 35°/320)

    θ = 24.2°

Direction is down (south) and left (west)

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