Regular hexagon ABCDEF is inscribed in a circle with a radius of 2 units.
2 answers:
For the triangle with side lengths equal to the radius of the circle is a equilateral.
so all the angles are 60 degrees
side lengths are the same as the radius as shown in the diagram.
so s = 2units
p = 2 x #ofSides
= 2 x 8 = 16
area of a hexagon formula proof and formula itslef is sligtly complicated.
Instead we can find the area of 1 triangle, and then multiply it by 6, since a hexagon is made up of these 6 triangles
area of triangle = 2x2 /2 = 2
2 x 6 = 12units^2
so all the angles are 60 degrees
side lengths are the same as the radius as shown in the diagram.
so s = 2units
p = 2 x #ofSides
= 2 x 8 = 16
area of a hexagon formula proof and formula itslef is sligtly complicated.
Instead we can find the area of 1 triangle, and then multiply it by 6, since a hexagon is made up of these 6 triangles
area of triangle = 2x2 /2 = 2
2 x 6 = 12units^2
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So hmm, if you notice the picture below
"y" would be the opposite to the 10° angle, and "x" would its adjacent
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solve for "y", to see how much north
and
solve for "x" to see how much west
make sure, that in both cases, your calculator is in Degree mode, since the angle is in degrees, as opposed to Radian mode
now... for the section B)
if notice the Reno-Miami line, and you were to draw a North line through it, anywhere in between, or at an endpoint like the in the picture at Reno, the "clockwise" angle, will always be the same, 100°
bear in mind ( no pun intended ), that Bearings use the North line, and the clockwise angle from it, as in the picture below
"y" would be the opposite to the 10° angle, and "x" would its adjacent
Reno is "y" north and "x" west from Miami
and
make sure, that in both cases, your calculator is in Degree mode, since the angle is in degrees, as opposed to Radian mode
now... for the section B)
if notice the Reno-Miami line, and you were to draw a North line through it, anywhere in between, or at an endpoint like the in the picture at Reno, the "clockwise" angle, will always be the same, 100°
bear in mind ( no pun intended ), that Bearings use the North line, and the clockwise angle from it, as in the picture below
Answer:
Option D)Neither solution is extraneous.
Step-by-step explanation:
we have
we know that
two possible solutions are x=-7 and x=1
<u><em>Verify each solution</em></u>
Substitute each value of x in the expression above and interpret the results
1) For x=-7
----> is true
therefore
x=-7 is not a an extraneous solution
2) For x=1
----> is true
therefore
x=1 is not a an extraneous solution
therefore
Neither solution is extraneous