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Ket [755]
3 years ago
13

Is 27/51 equal to 18/34

Mathematics
2 answers:
sergeinik [125]3 years ago
4 0
Yes.
27/51-18/34=0
if u subtract something from something and u get zero, it means those 2 numbers are equal.
Naya [18.7K]3 years ago
3 0
Yeah,they are equal
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___a value used to represent a true measurement that is not exact when an exact answer is not possible
Whitepunk [10]

Answer:

An estimate

Step-by-step explanation:

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Kassie is measuring two line segments. the first line segment is 35 centimetres long. the second line segment is 450 milimetres
Free_Kalibri [48]
1cm = 10mm
the 1st line segment is 35cm = 350mm
the 2nd line segment is 450mm = 45cm
6 0
3 years ago
Emily has a box where she stores her toys, the box has a height of 24 inches, a length of 40 inches, and a width of 10 inches. W
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Answer:

2)

Step-by-step explanation:

Volume of box = length * width * height

                         = 40 * 10 * 24

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Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
balu736 [363]
The tangent line to the curve can be determined by implicitly differentiating the equation of the curve. In this case, with the equation <span>y sin 12x = x cos 2y, (π/2, π/4), the implicit differentiation is 12 y cos 12x dx + sin 12 x dy = -2x sin 2y dy + cos 2y dx; dx (12 y cos 12x  - cos 2y) = dy (</span><span>-2x sin 2y - sin 12x). Hence

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6 0
3 years ago
3×
In-s [12.5K]

Answer:

1. x = 39.67

2. x = 15

3. x = 49.29

4. x = -12.8

5. x = 96

6. x = 42

7. x = 36

8. x = 0

9. x = 78

Step-by-step explanation:

Just remember to always isolate the unknown. Here are the solutions to your problem. I will explain each step for the first for you to give you an idea how the others were worked out.

1. \dfrac{3x}{7}-2 = 15  

Add 2 to both sides to get rid of -2 on the left side.

\dfrac{3x}{7}-2+(2)=15+(2)///dfrac{3x}{7}=17

Multiply both sides by 7 to get rid of 7 on the left side.

\dfrac{3x}{7}\times 7 = 17\times 7\\\\3x = 119

Divide both sides by 3 to get rid of 3 on the left side.

\dfrac{3x}{3} = \dfrac{119}{3}\\\\x = 39.67

You could also transpose everything by the x to the other side of the equation. Just remember that whatever OPERATION used on the original side, must be opposite on the other side. I'll use the second problem to show this.

\dfrac{2x}{5}+1=7

Transpose  1 on the left to the right. It is addition on the left, then it would be subtraction on the other side.

\dfrac{2x}{5}+1=7\\\\\dfrac{2x}{5}=7-1\\\\\dfrac{2x}{5}=6

Transpose 5 from the left side to the right. It is division on the left, then it would be multiplication on the right.

\dfrac{2x}{5}=6\\\\2x=6\times 5\\\\2x=30

Transpose 2 from the left side to the right. It is multiplication on the left, then it would be division on the right.

2x=30\\\\x=\dfrac{30}{2}\\\\x=15

Let's move on with the rest now.

3.

\dfrac{7x}{15}-1=22\\\\\dfrac{7x}{15}=22+1\\\\\dfrac{7x}{15}=23\\\\7x=23\times15\\\\7x=345\\\\x=\dfrac{345}{7}\\\\x=49.29

4.

\dfrac{5x}{8}+10=2\\\\\dfrac{5x}{8}=2-10\\\\\dfrac{5x}{8}=-8\\\\5x=-8\times8\\\\5x=-64\\\\x=\dfrac{-64}{5}\\\\x=-12.8

5.

\dfrac{x}{6}+4=20\\\\\dfrac{x}{6}=20-4\\\\\dfrac{x}{6}=16\\\\x=16\times6\\\\x=96

6.

\dfrac{x}{3}-4=10\\\\\dfrac{x}{3}=10+4\\\\\dfrac{x}{3}=14\\\\x=3\times14\\\\x=42

7.

\dfrac{x}{6}+2=8\\\\\dfrac{x}{6}=8-2\\\\\dfrac{x}{6}=6\\\\x=6\times6\\\\x=36

8.

\dfrac{x}{9}+8=8\\\\\dfrac{x}{9}=8-8\\\\\dfrac{x}{9}=0\\\\x=0\times9\\\\x=0

9.

\dfrac{x}{6}+7=20\\\\\dfrac{x}{6}=20-7\\\\\dfrac{x}{6}=13\\\\x=13\times6\\\\x=78

6 0
3 years ago
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