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Rom4ik [11]
3 years ago
6

Find Jenny's mistake​

Mathematics
2 answers:
Paul [167]3 years ago
5 0
The 3 time 5 while doing the first distribution property
shusha [124]3 years ago
3 0
Jenny is a mistake her whole life is nobody like her
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Please show your work<br> <img src="https://tex.z-dn.net/?f=1%5Cfrac%7B2%7D%7B3%7D%20%2B%202%5Cfrac%7B3%7D%7B4%7D" id="TexFormul
Shkiper50 [21]

Answer:

→1 \frac{2}{3}  + 2 \frac{3}{4}  \\  =  \frac{5}{3}  +  \frac{11}{4}  \\  =  \frac{20 + 33}{12}  \\  = \frac{53}{12}\\ =\boxed{4\frac{5}{12}}✓

  • <u>5</u><u>3</u><u>/</u><u>1</u><u>2</u> is the right answer.
6 0
3 years ago
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Convert each fraction to a decimal. Classify the decimal as terminating, non-terminating, repeating, or nonrepeating. If the dec
mixas84 [53]

Answer:

0.375

Step-by-step explanation:

I just divided 3 and 8

8 0
3 years ago
What is the equation of this line?
Margarita [4]

Answer: either b or c

Step-by-step explanation:

¸.•´*¨`*•✿ ✧・゚: *✧・゚:* Jax *:・゚✧*:・゚✧✯✿•*`¨*`•.¸✯

3 0
3 years ago
Suppose the Acme Drug Company develops a new drug, designed to prevent colds. The company states that the drug is equally effect
matrenka [14]

Answer:

a) Null hypothesis: the drug is equally effective for men and women (company's claim)

Alternative hypothesis: the drug effectiveness significantly differs for men and women.

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

b) If the P-value is smaller than the significance level, the null hypothesis is rejected. If not, the null hypothesis failed to be rejected.

c) In the explanation.

d) As the P-value (0.0342) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the drug effectiveness significantly differs for men and women.

The company's claim is rejected.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim of the company, will be stated in the null hypothesis. We will test if there is evidence against that claim to reject it or not.

Then, the test claim is that the drug effectiveness significantly differs for men and women.

The null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1 (women), of size n1=100 has a proportion of p1=0.38.

The sample 2 (men), of size n2=200 has a proportion of p2=0.51.

The difference between proportions is (p1-p2)=-0.13.

p_d=p_1-p_2=0.38-0.51=-0.13

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{38+102}{100+200}=\dfrac{140}{300}=0.467

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.467*0.533}{100}+\dfrac{0.467*0.533}{200}}\\\\\\s_{p1-p2}=\sqrt{0.002489+0.001244}=\sqrt{0.003733}=0.061

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.13-0}{0.061}=\dfrac{-0.13}{0.061}=-2.1276

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(z

As the P-value (0.0342) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the drug effectiveness significantly differs for men and women.

6 0
3 years ago
Drag each relation to the correct location on the table. Classify the relations according to whether or not they are functions.
ki77a [65]
They are functions because they are straight
4 0
3 years ago
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