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Sergeeva-Olga [200]
3 years ago
12

-8x15=__________________________

Mathematics
2 answers:
sertanlavr [38]3 years ago
6 0
The answer to -8 x 15 is -120.
n200080 [17]3 years ago
5 0
Your answer is -8x^(15)
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I NEED HELP WITH ME MATH
ruslelena [56]

ok so lets start of with the fact that the whole thing is 21 units.

So we do 21-9=12 so then we now know that the rectangle is 12 so then we do 12*8 units which is= 96 . Now the triangles. so the first one we know that its 8*3 and times it by 1/2 because two triangles is equal to a rectangle so the first triangle is 12 and now the second. its 9-3= 6 then its 6*8*1/2 which is equal to 24 so now the final answer is

96+12+24 which is equal to 132 so i'm guessing it 132 square units

5 0
3 years ago
Polygon ABCDEF has 6 sides. A is 170° C is 133° D is 102° he is 117° and F is 90°. What is the measure of b?
Zielflug [23.3K]

Answer:

B = 134^o

Step-by-step explanation:

n = 6 --- sides

A = 170^o

C = 107^o

D = 102^o

E = 117^o

F = 90^o

Required

The measure of B

The interior angles of a polygon is:

Angles = (n - 2) * 180

So, we have:

Angles = (6 - 2) * 180

Angles = 4 * 180

Angles = 720^o

The measure of B is calculated using:

A + B + C + D + E + F = 720

Substitute known values

107 + B + 170 + 102 + 117 + 90 = 720

Collect like terms

B + 107 + 170 + 102 + 117 + 90 = 720

B + 586 = 720

Collect like terms

B = 720 - 586

B = 134^o

4 0
3 years ago
A submarine is 730 m below sea level. An airplane that is directly over the submarine is 9,144 m above sea level. What is the ve
Rina8888 [55]
Submarine: -730
Airplane: 9,144
|-730-9,144|=|-9,874|=9,874
|d|: absolute value
The vertical distance between the submarine and airplane is 9,874 meters.
4 0
3 years ago
Read 2 more answers
May I have some help please?
MakcuM [25]

Answer:

If this is solving for a hypotenuse, the answer is 8.

Step-by-step explanation:

a^2 + b^2 = c^2

6^2 b^2 = 10^2

36 + b^2 = 100

100 - 36 = 64

The square root of 64 is 8.

6 0
3 years ago
Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.
gladu [14]

Answer:

Vertical asymptote: x=3

Horizontal asymptote: f(x) =2

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

f (x) = -\dfrac{1 }{ x-3} +2

One root, x = 3.5

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5

One root, x = 3.5

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) \rightarrow \infty

For all, other values of x , f(x) is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is \frac{1}{x-3}.

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) \rightarrow \infty.

-\dfrac{1 }{ x-3} +2 \rightarrow \infty

It is possible only when

x-3=0\\\Rightarrow x=3

\therefore vertical asymptote: x=3

Horizontal Asymptote is the value of f(x) , where value of x \rightarrow \infty.

x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2

\therefore Horizontal asymptote: f(x) =2

Please refer to the graph of given function as shown in the attached image.

5 0
3 years ago
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