The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
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The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
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Answer:
(-5, 5), (2, 8), (-6, 0)
Step-by-step explanation:
It is convenient to graph the solution, then plot the points to see which fall in the solution area.
The point (3, 9) falls on the boundary line, which is <em>not</em> part of the solution set.
The points that are solutions are ...
B(-5, 5)
E(2, 8)
F(-6, 0)
Answer:
Cubic
Step-by-step explanation:
A cubic polynomial has a highest degree of 3.
In this polynomial, we see "q^3" meaning that q is raised to the 3rd power, making this a cubic polynomial.
Hope this helps!
Answer:
m = 1.8
Step-by-step explanation:
Given data is as follows :
x 1 2 3 4 5 6
f 1 4 7 m 6 3
We need to find the value of m if the mean of the data is 3.8.
Mean = sum of observations/no. of observations
So,
So, the value of m is equal to 1.8.
Answer:
he has received negative positive punishment...? I"M SORRY IF IT"S WRONG!!!
Step-by-step explanation:
