The area of a regular hexagon is 55 in^2. Find the length of a side. Round your answer to the nearest tenth. I know the answer i
s 4.6 in., but I have no idea how to solve it.
1 answer:
Polygon area = n*side length^2 / [4*tan(180/n)]
side length^2 = polygon area * [4*tan(180/n)] / n
where n is the number of sides
side length^2 = 55 sq inches * (4*tan(180/6)) / 6
side length^2 = 55 sq inches * 4 * tan (30) / 6
side length^2 = (55 sq inches * 4 * 0.57735) / 6
side length^2 =
<span>
<span>
<span>
127.017
</span>
</span>
</span>
/ 6
side length^2 =
<span>
<span>
<span>
21.1695
</span>
</span>
</span>
side length = square root (
<span>
<span>
<span>
21.1695
</span>
</span>
</span>
)
side length =
<span>
<span>
<span>
4.6010324928
</span>
</span>
</span>
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-9
Answer:
39=22
28-6 equal to 22 so 39= 22
Answer:
√(137)
Step-by-step explanation:
First, you will need to find the other side length.....then you can use the Pythagorean Theorem to find the diagonal:
L x W = 44
4 x W = 44
W =11
Now the Pythag, Theorem:
diagonal^2 = 4^2 + 11^2
d^2 = 16+121
d^2 = 137
d = √(137)
There are multiple answers like 15 16 17 18 19 and also 20. Are the correct answers
Answer:
Its is just 0
Step-by-step explanation:
