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babunello [35]
3 years ago
15

What happens if 0 is one of the coordinates?

Mathematics
2 answers:
Gnesinka [82]3 years ago
4 0

Answer:

Then it would be on a line

Step-by-step explanation:

aleksandrvk [35]3 years ago
3 0

Answer:

Its is just 0

Step-by-step explanation:

You might be interested in
Find the circumference of a circle with the diameter of 10 inches. Leave your answers in form of pi
MrRa [10]

Answer:

Circumference = 10π

Step-by-step explanation:

First identify the circumference formula as such:

2πr (where r ⇒ radius, π ⇒ pi)

Knowing 2 times the radius (2r) in the formula can be rewritten as the diameter, the formula itself can be rewritten as:

πd (where d ⇒ diameter, π ⇒ pi)

If we know the diameter = 10 inches, substitute in the circumference formula πd to get:

π * 10 inches = 10 * π inches = 10π inches

4 0
3 years ago
Is the answer B correct?
VashaNatasha [74]
If you do the elimination process, here it is.

- A : Too small

+ B : I think so

- C : I little too big

- D : Way too big
7 0
3 years ago
Read 2 more answers
Which of the following is a polynomial function in standard form with zeros at –8, –1, and 3?
telo118 [61]
The answer is A because zeros of polynomial functions are found by setting each factor equal to zero and solving for x. The zeros of a function will be the opposite sign of the numbers inside each factor.
8 0
3 years ago
Read 2 more answers
A swimming pool has a length of 25 ft, a width of 15 fr, and a depth of 4 ft. What is the volume of the water in this pool when
timofeeve [1]

Answer:

1312.5 cubic feet

Step-by-step explanation:

Let the swimming pool be a rectangular prism

The volume of a rectangular prism is:

Volume = length * width * depth

Length = 25 (given)

Width = 15 (given)

The depth is 4ft, but they want the volume when water is 6 inches FROM THE TOP, that is, out of 4 feet, 6 inches (1/2 feet) IS NOT FILLED. So the depth of water is

4 - 1/2 = 3.5 feet

So, we can say

Depth = 3.5 (found)

Hence, the volume would be:

Volume = 25 * 15 * 3.5 = 1312.5 cubic feet

8 0
3 years ago
Using t=tanx/2, write an expression for sinx and cosx in terms of t.
Dafna11 [192]

Assume 0 < <em>x</em>/2 < <em>π</em>/2. Then

tan²(<em>x</em>/2) + 1 = sec²(<em>x</em>/2)   ===>   sec(<em>x</em>/2) = √(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - <em>t</em> ²)

We also know that

sin²(<em>x</em>/2) + cos²(<em>x</em>/2) = 1   ===>   sin(<em>x</em>/2) = √(1 - cos²(<em>x</em>/2))

Recall the double angle identities:

cos(<em>x</em>) = 2 cos²(<em>x</em>/2) - 1

sin(<em>x</em>) = 2 sin(<em>x</em>/2) cos(<em>x</em>/2)

Then

cos(<em>x</em>) = 2/(1 - <em>t</em> ²) - 1 = (1 + <em>t</em> ²)/(1 - <em>t</em> ²)

sin(<em>x</em>) = 2 √(1 - 1/(1 - <em>t</em> ²)) / √(1 - <em>t</em> ²) = 2<em>t</em>/(1 - <em>t</em> ²)

7 0
2 years ago
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