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Mice21 [21]
3 years ago
11

9. What number is 70% of 40?(Use the letter b for the variable.)

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
8 0
70% of 40= 0.7x40=28. 
yKpoI14uk [10]3 years ago
6 0
B=28 That is the answer on my calculator i put 70% of 40 
 
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identify the expression that is not equivalent to the other three. Explain your reasoning. x-2+3x , 4(x-2) , -2+7x-3x, 4x-2
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4(x-2) is different because if you distribute the expression it would be 4x-8 and the rest of the expressions are simplified to 4x-2
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Can you guys solve this for me please
djyliett [7]

Answer:

50°

Step-by-step explanation:

all triangles = 180°

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A car travels 53.6 miles in an hour.
valina [46]

Answer:

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Step-by-step explanation:

3 0
3 years ago
The quantity of 10 more than d multiplied by 5
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(10 + D)x 5

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If youre looking for an equation, here it is!

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suppose that n is a positive integer written in base 10. prove that n is divisible by 3 if and only if the sum of its decimal di
Goshia [24]

Modulo - The result of multiplying the original number by three and the result of multiplying the digits by three must be the same.

What is modulo?

In mathematics, the phrase modulo, which literally means "with respect to a modulus of," is frequently used to claim that two different mathematical objects can be regarded as comparable if their difference is explained by a third component.

Using the Fermat's little theorem:

x^n-1 =(x-1)(x^{n-1}+x^{n-2}+....+x+1)

when x=10. You may easily establish the identity by multiplying it term by word. All terms cancel, excluding the first and last ones. Therefore, any power of ten minus one is divisible by nine, and consequently, by three

Now consider a multi-digit natural number, 43617 for example.

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= 4*9999+3*999+6*99+1*9+(4+3+6+1+7)

Other than the sum of the digits, every term on the right is divisible by 3. The result of multiplying the original number by three and the result of multiplying the digits by three must be the same.

to learn more about exponents and power visit:

brainly.com/question/19120853

#SPJ4

5 0
1 year ago
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